0
  1. 我需要在聊天中获取所有消息。我使用 C# 和 TLSharp 库。

  2. 我授权,成功获得令牌等。

  3. 但是当我试图在一个循环中获取消息时,我将进入一个无限循环。

  4. 所以带有结果的文本永远不会出现在文本框中。我想知道我做错了什么以及如何解决它。谢谢。

    using TeleSharp.TL;
    using TeleSharp.TL.Messages;
    using TLSharp.Core;
    //using other standard...
    
    //code for authorization etc. is skipped
    
     int VKFID = 1175259547; //ID of the chat
     int offset = 0;
     int n = 1;
     StringBuilder sb = new StringBuilder();
     TelegramClient client = new TelegramClient(<key>, <hash>);
     TLUser user;
    
     private DateTime ConvertFromUnixTimestamp(double timestamp)
     {
         DateTime origin = new DateTime(1970, 1, 1, 0, 0, 0, 0);
         return origin.AddSeconds(timestamp);
     }
    
     private async void button3_Click(object sender, EventArgs e)
     {
         sb.Append("#\tDate\tTime\tMID\tTUID\tText" + Environment.NewLine);
         TLDialogsSlice dialogs = (TLDialogsSlice)await client.GetUserDialogsAsync();
         TLChannel chat = dialogs.Chats.Where(c => c.GetType() == typeof(TLChannel)).Cast<TLChannel>().FirstOrDefault(c => c.Id == VKFID);
         TLInputPeerChannel inputPeer = new TLInputPeerChannel() { ChannelId = chat.Id, AccessHash = (long)chat.AccessHash };
         while (true)
         {
             try
             {
                 TLChannelMessages res = await client.SendRequestAsync<TLChannelMessages>
                 (new TLRequestGetHistory() { Peer = inputPeer, Limit = 1000, AddOffset = offset, OffsetId = 0 });
                 var msgs = res.Messages;
                 if (res.Count > offset)
                 {
                     offset += msgs.Count;
                     foreach (TLAbsMessage msg in msgs)
                     {
                         if (msg is TLMessage)
                         {
                             TLMessage message = msg as TLMessage;
                             sb.Append(n.ToString() + "\t" +
                                 ConvertFromUnixTimestamp(message.Date).ToLocalTime().ToString("dd'.'MM'.'yyyy") + "\t" +
                                 ConvertFromUnixTimestamp(message.Date).ToLocalTime().ToString("HH':'mm':'ss") + "\t" +
                                 message.Id + "\t" + message.FromId + "\t" + message.Message + Environment.NewLine);
                         }
                         if (msg is TLMessageService)
                             continue;
                         n++;
                     }
                     Thread.Sleep(22000); //to avoid TelegramFloodException
                 }
                 else
                     break;
             }
             catch (Exception ex)
             {
                 MessageBox.Show(ex.Message);
                 break;
             }
             finally
             {
                 await Task.Delay(22000); //to avoid TelegramFloodException
             }
         }
         textBox2.Text = sb.ToString();
         MessageBox.Show("Done");
     }
    
4

2 回答 2

1

现在有WTelegramClient库,使用最新的 Telegram Client API 协议(以用户身份连接,而不是机器人)。

该库非常完整,但使用起来也非常简单。按照GitHub 上的 README进行简单介绍。

连接、查找您的聊天和检索所有消息可以这样完成:

using TL;
using System.Linq;

const int TargetChatId = 1175259547;

using var client = new WTelegram.Client(); // or Client(Environment.GetEnvironmentVariable)
await client.LoginUserIfNeeded();
var chats = await client.Messages_GetAllChats(null);
InputPeer peer = chats.chats.First(chat => chat.ID == TargetChatId);
for (int offset = 0; ;)
{
    var messagesBase = await client.Messages_GetHistory(peer, 0, default, offset, 1000, 0, 0, 0);
    if (messagesBase is not Messages_ChannelMessages channelMessages) break;
    foreach (var msgBase in channelMessages.messages)
        if (msgBase is Message msg)
        {
            // process the message
        }
    offset += channelMessages.messages.Length;
    if (offset >= channelMessages.count) break;
}
于 2021-10-16T00:00:22.200 回答
0

您可以尝试在 Thead.Sleep(22000) 之前刷新您的文本框吗?

    textBox2.Text += sb.ToString();
    Application.DoEvents();
    Thread.Sleep(22000);

执行此操作的其他方式可以是使用 BackgroundWorker,其方式与用于管理 ProgressBar 的方式相同。

于 2021-01-05T10:15:19.743 回答