I want to find both first day and last day of each month for the previous 6 months from today, with pure vanilla JavaScript. How can I do this?
2 回答
0
这是一个可能对您有所帮助的示例。
var today = new Date();
for(var i = 6; i > 0; i -= 1) {
var firstDay = new Date(new Date(new Date().setMonth(today.getMonth() - i)).setDate(1)).getDate();
var firstMonth = new Date(new Date(new Date().setMonth(today.getMonth() - i)).setDate(1)).getMonth();
var firstYear = new Date(new Date(new Date().setMonth(today.getMonth() - i)).setDate(1)).getFullYear();
console.log(firstDay+'/'+firstMonth+'/'+firstYear);
var lastDay = new Date(new Date(new Date().setMonth(today.getMonth() - i)).setDate(0)).getDate();
console.log(lastDay+'/'+firstMonth+'/'+firstYear);
}
于 2020-12-22T06:53:53.547 回答
0
谢谢尼拉夫!
这是基于 Nirav 答案的最终代码,并有一个小修复:
var today = new Date();
for (var i = 5; i >= 0; i -= 1) {
var firstDay = new Date(
new Date(new Date().setMonth(today.getMonth() - i)).setDate(1)
).getDate();
var firstMonth = new Date(
new Date(new Date().setMonth(today.getMonth() - i)).setDate(1)
).getMonth();
var firstYear = new Date(
new Date(new Date().setMonth(today.getMonth() - i)).setDate(1)
).getFullYear();
console.log(firstDay + "/" + firstMonth + "/" + firstYear);
var lastDay = new Date(
new Date(new Date().setMonth(today.getMonth() - i)).setDate(0)
).getDate();
console.log(lastDay + "/" + firstMonth + "/" + firstYear);
}
于 2020-12-22T16:54:47.643 回答