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在 playwright-python 中,我知道我可以获得elementHandleusing querySelector().

示例(同步):

from playwright import sync_playwright

with sync_playwright() as p:
    for browser_type in [p.chromium, p.firefox, p.webkit]:
        browser = browser_type.launch()
        page = browser.newPage()  
        page.goto('https://duckduckgo.com/')
        element = page.querySelector('input[id=\"search_form_input_homepage\"]')
    

如何基于 this 获取与 this 相关的 an 元素elementHandle?即父母,祖父母,兄弟姐妹,孩子处理?

4

1 回答 1

4

querySelector()/querySelectorAllXPath(XML 路径语言)一起使用可以让您检索elementHandle(分别是句柄的集合)。一般来说,XPath可用于浏览 XML 文档中的元素和属性。

from playwright import sync_playwright

with sync_playwright() as p:
    for browser_type in [p.chromium, p.firefox, p.webkit]:
        browser = browser_type.launch(headless=False)
        page = browser.newPage()
        page.goto('https://duckduckgo.com/')
        element = page.querySelector('input[id=\"search_form_input_homepage\"]')
        
        parent = element.querySelector('xpath=..')
        grandparent = element.querySelector('xpath=../..')
        siblings = element.querySelectorAll('xpath=following-sibling::*')
        children = element.querySelectorAll('xpath=child::*')

        browser.close()
于 2020-12-21T22:31:44.910 回答