您可以尝试使用VALUES
表值构造函数和FOR JSON AUTO
. 如文档中所述,当...指定 AUTO 选项时,JSON 输出的格式将根据 SELECT 列表中的列顺序及其源表自动确定。
桌子:
CREATE TABLE Tbl (
Id int,
ItemName varchar(10),
CategoryId int,
ItemDate date
)
INSERT INTO Tbl
VALUES
(1, 'ABC', 100, '1/1/2020'),
(2, 'DEF', 200, '2/2/2020')
陈述:
SELECT t.Id, data.[key], data.[value]
FROM Tbl t
CROSS APPLY (VALUES
('ItemName', CONVERT(varchar(max), ItemName)),
('CategoryId', CONVERT(varchar(max), CategoryId)),
('ItemDate', CONVERT(varchar(max), ItemDate))
) Data ([key], [value])
FOR JSON AUTO
结果:
[
{
"Id":1,
"Data":[
{"key":"ItemName", "value":"ABC"},
{"key":"CategoryId","value":"100"},
{"key":"ItemDate","value":"2020-01-01"}
]
},
{
"Id":2,
"Data":[
{"key":"ItemName", "value":"DEF"},
{"key":"CategoryId", "value":"200"},
{"key":"ItemDate", "value":"2020-02-02"}
]
}
]
作为附加选项,您可以尝试为每一行构建内部 JSON:
SELECT
Id,
(
SELECT [key], [value]
FROM (VALUES
('ItemName', CONVERT(varchar(max), ItemName)),
('CategoryId', CONVERT(varchar(max), CategoryId)),
('ItemDate', CONVERT(varchar(max), ItemDate))
) v ([key], [value])
FOR JSON PATH
) AS Data
FROM Tbl
FOR JSON AUTO