2

我有 2 个具有父数组和子数组的分组数组，我想合并这 2 个具有相同父数组的数组，但是我只复制具有唯一顺序的子数组，我在互联网上搜索了很多文章但尚未找到解决方案。请帮我。有我的代码

var groupOrder = [
  {
    group_time_str: "25 Apr 2019",
    orders: [
      {
        vertical_id: "1",
        vertical_category: "A"
      },
      {
        vertical_id: "2",
        vertical_category: "B"
      }
    ]
  },
  {
    group_time_str: "26 Apr 2019",
    orders: [
      {
        vertical_id: "1",
        vertical_category: "A"
      },
      {
        vertical_id: "2",
        vertical_category: "B"
      },
      {
        vertical_id: "3",
        vertical_category: "C"
      }
    ]
  }
];
var groupOrder2 = [
  {
    group_time_str: "26 Apr 2019",
    orders: [
      {
        vertical_id: "3",
        vertical_category: "C"
      },
      {
        vertical_id: "4",
        vertical_category: "D"
      }
    ]
  },
  {
    group_time_str: "27 Apr 2019",
    orders: [
      {
        vertical_id: "1",
        vertical_category: "A"
      },
      {
        vertical_id: "2",
        vertical_category: "B"
      }
    ]
  }
];
const combine = [...groupOrder, ...groupOrder2];
const groupBy = combine.reduce((acc, cur) => {
  acc[cur.group_time_str]
    ? (acc[cur.group_time_str].orders = [
        ...acc[cur.group_time_str].orders,
        ...cur.orders
      ])
    : (acc[cur.group_time_str] = cur);
  return acc;
}, {});
console.log(groupBy);
body {
  font-family: sans-serif;
}
<h1>Grouped Order</h1>

您会看到在2019 年 4 月 26 日的组中有重复

{
   vertical_id: "3",
   vertical_category: "C"
},

我怎样才能删除重复的？请帮助我，谢谢

4

2 回答 2

1

尝试减少第一个数组以仅获取不匹配的项目，而不是在开始时合并数组：

const groupOrder = [{group_time_str: "25 Apr 2019",orders: [{vertical_id: "1",vertical_category: "A"},{vertical_id: "2",vertical_category: "B"}]},{group_time_str: "26 Apr 2019",orders: [{vertical_id: "1",vertical_category: "A"},{vertical_id: "2",vertical_category: "B"},{vertical_id: "3",vertical_category: "C"}]}];
const groupOrder2 = [{group_time_str: "26 Apr 2019",orders: [{vertical_id: "3",vertical_category: "C"},{vertical_id: "4",vertical_category: "D"}]},{group_time_str: "27 Apr 2019", orders: [{vertical_id: "1",vertical_category: "A"},{vertical_id: "2",vertical_category: "B"}]}];

const result = groupOrder.reduce((arr, g1) => {
  const g2match = groupOrder2.find(
    g2 => g2.group_time_str === g1.group_time_str
  );
  if (g2match) {
    const orders = g1.orders.filter(
      g1o =>
        !g2match.orders.find(
          m =>
            g1o.vertical_id === m.vertical_id &&
            g1o.vertical_category === m.vertical_category
        )
    );
    g2match.orders = [...g2match.orders, ...orders];
    return arr;
  }
  return [...arr, { ...g1 }];
}, []);

console.log([...result, ...groupOrder2]);

于 2020-12-11T14:03:06.840 回答
0

您可以执行以下过滤 cur.orders 以删除重复项，

var groupOrder = [
  {
    group_time_str: "25 Apr 2019",
    orders: [
      {
        vertical_id: "1",
        vertical_category: "A"
      },
      {
        vertical_id: "2",
        vertical_category: "B"
      }
    ]
  },
  {
    group_time_str: "26 Apr 2019",
    orders: [
      {
        vertical_id: "1",
        vertical_category: "A"
      },
      {
        vertical_id: "2",
        vertical_category: "B"
      },
      {
        vertical_id: "3",
        vertical_category: "C"
      }
    ]
  }
];
var groupOrder2 = [
  {
    group_time_str: "26 Apr 2019",
    orders: [
      {
        vertical_id: "3",
        vertical_category: "C"
      },
      {
        vertical_id: "4",
        vertical_category: "D"
      }
    ]
  },
  {
    group_time_str: "27 Apr 2019",
    orders: [
      {
        vertical_id: "1",
        vertical_category: "A"
      },
      {
        vertical_id: "2",
        vertical_category: "B"
      }
    ]
  }
];
const combine = [...groupOrder, ...groupOrder2];
const groupBy = combine.reduce((acc, cur) => {
  acc[cur.group_time_str]
    ? (acc[cur.group_time_str].orders = [
        ...acc[cur.group_time_str].orders,
        ...cur.orders.filter(item => acc[cur.group_time_str].orders.findIndex(accOrder => item['vertical_id'] === accOrder['vertical_id'] && item['vertical_category'] === accOrder['vertical_category']) <= -1)
      ])
    : (acc[cur.group_time_str] = cur);
  return acc;
}, {});
console.log(groupBy);
body {
  font-family: sans-serif;
}
<h1>Grouped Order</h1>

于 2020-12-11T06:31:30.330 回答