python - 如何更改 Django 模型返回的值？

Question

我试图让我Product kind的名字与我声明的一样，而不是我得到的数字。让我更清楚一点：下面是我的Product Kinds；

PRODUCT_KINDS = (
    ("1","Electronic"),
    ("2","Furniture"),
    ("3", "Bedroom"),
    ("4","Dining")

)

下面这张图片是我的 django-admin 面板，一切看起来都很完美，因为我可以得到我的每一种。

但是，当我尝试从api/productsurl 获取这些数据时，我得到了这些数据

[
    {
        "image": null,
        "name": "Headphones",
        "kind": "1",
        "price": 250.99,
        "description": "No description for this item.",
        "is_featured": true
    },
    {
        "image": null,
        "name": "Watch",
        "kind": "3",
        "price": 12.5,
        "description": "No description for this item.",
        "is_featured": true
    },
    {
        "image": null,
        "name": "T-shirt",
        "kind": "2",
        "price": 12.99,
        "description": "No description for this item.",
        "is_featured": true
    },
    {
        "image": null,
        "name": "Ali Ziya ÇEVİK",
        "kind": "1",
        "price": 1212.0,
        "description": "No description for this item.",
        "is_featured": false
    }
]

如您所见，在我的 django-admin 面板中，我得到了 kind 的名称，但在 API 中，我得到了它的索引。

下面是我的serializer：

from rest_framework import serializers
from .models import Product


class ProductSerializer(serializers.ModelSerializer):
    #kind = serializers.CharField(source = 'kind')
    #print(kind)
    class Meta:

        model = Product
        fields = ['image', 'name', 'kind',
                  'price', 'description', 'is_featured']

Answer 1

您可以从Model.get_FOO_display()方法中设置值的来源

kind = serializers.CharField(source = 'get_kind_display')

Answer 2

您可以尝试使用 get_FOO_display 使用字段源： https ://docs.djangoproject.com/en/1.8/ref/models/instances/#django.db.models.Model.get_FOO_display

from rest_framework import serializers
from .models import Product


class ProductSerializer(serializers.ModelSerializer):

    kind = serializers.CharField(source='get_kind_display')
    class Meta(object):
        model = Product
        fields = ('image', 'name', 'kind','price', 'description', 'is_featured')