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我想编写一个 2 人游戏，其中一个玩，wsad另一个玩yghj. 如果其中一个玩家一直按住键，KeyListener则无法听其他键。我应该怎么做才能让他们两个都能被听到？

@Override
public void keyPressed(KeyEvent e) {
    if (e.getKeyCode() == 39)
        player1.setBounds((dim_player1.width += 5), dim_player1.height, 80, 120);
    else if (e.getKeyCode() == 37)
        player1.setBounds((dim_player1.width -= 5), dim_player1.height, 80, 120);
    else if (e.getKeyCode() == 40)
        player1.setBounds(dim_player1.width, (dim_player1.height += 5), 80, 120);
    else if (e.getKeyCode() == 38)
        player1.setBounds(dim_player1.width, (dim_player1.height -= 5), 80, 120);

}
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1 回答 1

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嗯。我的 TZ 早上 6 点，所以我可能错了，但是 - 线程。将键盘状态存储在线程安全的集合/映射中，在按下事件时更新集合/映射，使用每个游戏滴答的状态来执行结果。

或者只使用布尔数组。在大多数情况下也能正常工作。例如：

static public enum camera_action {
  ESCAPE, // e.g. exit to main menu, terminate mouse capture etc
  MV_FORWARD, MV_BACKWARD, MV_STRAFE_LEFT, MV_STRAFE_RIGHT, MV_JUMP, MV_CROUCH, // etc
}

final protected SC_HashMap<Integer, camera_action> keymap = new SC_HashMap.linked<>();
protected boolean[] action_state = new boolean[camera_action.values().length];

final protected void set_default_keymap() {
  keymap.put( KeyEvent.VK_SHIFT, camera_action.MV_JUMP );
  keymap.put( KeyEvent.VK_CONTROL, camera_action.MV_CROUCH );
  keymap.put( KeyEvent.VK_W, camera_action.MV_FORWARD );
  keymap.put( KeyEvent.VK_S, camera_action.MV_BACKWARD );
  keymap.put( KeyEvent.VK_A, camera_action.MV_STRAFE_LEFT );
  keymap.put( KeyEvent.VK_D, camera_action.MV_STRAFE_RIGHT );
  keymap.put( KeyEvent.VK_ESCAPE, camera_action.ESCAPE );
}

protected void set_action_state( camera_action a, boolean new_state ) {
  action_state[a.ordinal()] = new_state;
}

protected boolean get_action_state( camera_action a ) {
  return action_state[a.ordinal()];
}

public void reset_action_state() {
  action_state = new boolean[camera_action.values().length];
}

@Override
public void keyPressed( KeyEvent e ) {
  camera_action a = keymap.get( e.getKeyCode() );
  if ( a != null )
    set_action_state( a, true );
}

@Override
public void keyReleased( KeyEvent e ) {
  camera_action a = keymap.get( e.getKeyCode() );
  if ( a != null )
    set_action_state( a, false );
}

我知道甲骨文关于 Enum.ordinal() 的政策——我对此毫不在意。如果 EnumSet 能用，我也能用。ordinal() 的契约足够牢固。

而且 - 是的。可能被Swing 的 KeyListener 和同时按下的多个键所欺骗。

于 2012-12-12T05:13:27.130 回答