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我正在尝试编写一个脚本来更新 JS 中以冒号分隔的参数的 URL，因为页面内容是通过 AJAX 加载的。

文档结构是这样的：

Format:
<div class="filter" id="formats">
  <a class="active" href="https://cdpn.io/page/">All</a>
  <a href="https://cdpn.io/page/format:foo">Foo</a>
  <a href="https://cdpn.io/page/format:bar">Bar</a>
  <a href="https://cdpn.io/page/format:baz">Baz</a>
<div>

<br>

Topic:
<div class="filter" id="topics">
  <a class="active" href="https://cdpn.io/page/">All</a>
  <a href="https://cdpn.io/page/topic:foo">Foo</a>
  <a href="https://cdpn.io/page/topic:bar">Bar</a>
  <a href="https://cdpn.io/page/topic:baz">Baz</a>
</div>
  
<br>
  
Sort By:
<div class="filter" id="sort">
  <a href="https://cdpn.io/page/sort:topic-asc">Topic Asc</a>
  <a href="https://cdpn.io/page/sort:topic-desc">Topic Desc</a>
  <br>
  <a href="https://cdpn.io/page/sort:title-asc">Title Asc</a>
  <a href="https://cdpn.io/page/sort:title-desc">Title Desc</a>
</div>

  <br>
  Url loaded:
<div id="content">
  https://cdpn.io/page
</div>

仅#content由 AJAX 库更新，所有链接都需要“手动”更改。

例如：如果我单击过滤器链接https://example.com/page/topic:foo，如尚不存在，并在它们不存在时将其删除。https://example.com/page/format:barhttps://example.com/page/topic:foo/format:bar

我以为我已经通过映射对象数组中的所有参数来解决它，然后使用我在 StackOverflow 上找到的片段进行合并并返回字符串，但我的逻辑似乎有错误，我无法确定它……</p> 

const mergeByProperty = (target, source, prop) => {
  source.forEach(sourceElement => {
    let targetElement = target.find(targetElement => {
      return sourceElement[prop] === targetElement[prop];
    })
    targetElement ? Object.assign(targetElement, sourceElement) : target.push(sourceElement);
  })
}

for (el of document.querySelectorAll('a')) {
  el.addEventListener('click', (e) => {
    e.preventDefault();
    loadNewContent(e.target);
  })
}

const loadNewContent = (target) => {
  document.querySelector('#content').innerText = target 
  // this is where page content is fetched & appended etc, then:
  updateLinks(target)
}

const updateLinks = (trigger) => {
  document.querySelectorAll('a').forEach(linkToUpdate => {
    linkToUpdate.href = mergeURLs(linkToUpdate.href, trigger.href);
  })
}

function mergeURLs(url1, url2) {
  let params1 = getParams(url1)
  let params2 = getParams(url2)
  mergeByProperty(params1, params2, 'param')
  let newParamString = params1.map(s => `${s.param}:${s.value}`).join('/');
  return `${window.location.origin}/page/${newParamString}`;
}

这是我尝试过的codepen的链接。

https://codepen.io/moevbiz/pen/OJRNNex?editors=0011

感谢您的任何提示或建议……</p>

4

1 回答 1

0

解决方案：我没有从 URL 参数创建对象并尝试合并它们，而是使用正则表达式替换现有参数。

Codepen：https ://codepen.io/moevbiz/pen/gOwrKYO?editors=0011

链接获取如下数据属性：

<a data-param="format" data-param-string="format:foo" href="https://cdpn.io/page/format:foo">Foo</a>

工作代码：

for (el of document.querySelectorAll('a')) {
  el.addEventListener('click', (e) => {
    e.preventDefault();
    loadNewContent(e.target);
  })
}

const loadNewContent = (trigger) => {
  document.querySelector('#content').innerText = trigger;
  updateLinks(trigger)
}

const updateLinks = (trigger) => {
  document.querySelectorAll('a').forEach(linkToUpdate => {
    if (linkToUpdate.dataset.param != trigger.dataset.param) { // only update links that don't belong to the same group of elements
      linkToUpdate.href = merge(linkToUpdate.href, trigger.dataset.param, trigger.dataset.paramString); 
    }
  })
}

const merge = (url, param, paramString) => {
  let newUrl;
  let regex = new RegExp(`(${param}:[^\/]*)`, "g")

  function replaceParam(url, newParamString) {
    return url.replace(regex, newParamString)
  }
  
  if (url.includes(`${param}:`)) { // replace param if it already exists, else append it to the href
    newUrl = replaceParam(url, paramString)
  } else {
    newUrl = url.concat('/' + paramString)
  }
  return newUrl.replace(/([^:])(\/\/+)/g, '$1/'); // remove double slashes except after https://
}
于 2020-12-07T13:54:20.507 回答