33

我有一个带有以下代码的 mysqli 查询:

$db_usag->query("UPDATE Applicant SET phone_number ='$phone_number', 
street_name='$street_name', city='$city', county='$county', zip_code='$zip_code', day_date='$day_date', month_date='$month_date',
 year_date='$year_date' WHERE account_id='$account_id'");

但是,所有数据都是从 HTML 文档中提取的,因此为了避免错误,我想使用准备好的语句。我找到了 PHP 文档,bind_param()但没有 UPDATE 示例。

4

1 回答 1

70

An UPDATE works the same as an insert or select. Just replace all the variables with ?.

$sql = "UPDATE Applicant SET phone_number=?, street_name=?, city=?, county=?, zip_code=?, day_date=?, month_date=?, year_date=? WHERE account_id=?";

$stmt = $db_usag->prepare($sql);

// This assumes the date and account_id parameters are integers `d` and the rest are strings `s`
// So that's 5 consecutive string params and then 4 integer params

$stmt->bind_param('sssssdddd', $phone_number, $street_name, $city, $county, $zip_code, $day_date, $month_date, $year_date, $account_id);
$stmt->execute();

if ($stmt->error) {
  echo "FAILURE!!! " . $stmt->error;
}
else echo "Updated {$stmt->affected_rows} rows";

$stmt->close();
于 2011-06-29T01:04:20.390 回答