1

这是我的代码设置：

import pandas as pd
    
    df = {'Datetime':  ['2020-12-01 00:00:00', '2020-12-01 01:00:00','2020-12-01 02:00:00',
                        '2020-12-01 03:00:00', '2020-12-01 04:00:00' , '2020-12-01 05:00:00' ,
                        '2020-12-01 06:00:00' , '2020-12-01 09:00:00' , '2020-12-01 12:00:00' ,
                        '2020-12-01 18:00:00' , '2020-12-02 00:00:00'
                       ]
           
            }
    
    df = pd.DataFrame(df , columns = ['Datetime'])
    
    df["Datetime"] = pd.to_datetime(df['Datetime'])
    
    df

这会产生一个具有以下形式的数据框：

    Datetime
0   2020-12-01 00:00:00
1   2020-12-01 01:00:00
2   2020-12-01 02:00:00
3   2020-12-01 03:00:00
4   2020-12-01 04:00:00
5   2020-12-01 05:00:00
6   2020-12-01 06:00:00
7   2020-12-01 09:00:00
8   2020-12-01 12:00:00
9   2020-12-01 18:00:00
10  2020-12-02 00:00:00

我想要做的是找到值之间的中点并在数据框中创建两个新列。两个新列是“开始时间”和“结束时间”。“开始时间”是该时间与前一次之间的中点（如果存在）。“结束时间”是该时间与下一次之间的中点（如果存在）。如果不存在，则使用当前时间。

这是我希望代码生成的内容：

    Datetime    Start Time  End Time
0   2020-12-01 00:00:00     2020-12-01 00:00:00     2020-12-01 00:30:00
1   2020-12-01 01:00:00     2020-12-01 00:30:00     2020-12-01 01:30:00
2   2020-12-01 02:00:00     2020-12-01 01:30:00     2020-12-01 02:30:00
3   2020-12-01 03:00:00     2020-12-01 02:30:00     2020-12-01 03:30:00
4   2020-12-01 04:00:00     2020-12-01 03:30:00     2020-12-01 04:30:00
5   2020-12-01 05:00:00     2020-12-01 04:30:00     2020-12-01 05:30:00
6   2020-12-01 06:00:00     2020-12-01 05:30:00     2020-12-01 07:30:00
7   2020-12-01 09:00:00     2020-12-01 07:30:00     2020-12-01 10:30:00
8   2020-12-01 12:00:00     2020-12-01 10:30:00     2020-12-01 15:00:00
9   2020-12-01 18:00:00     2020-12-01 15:00:00     2020-12-01 21:00:00
10  2020-12-02 00:00:00     2020-12-02 21:00:00     2020-12-02 00:00:00

任何帮助设置此问题将不胜感激。

4

1 回答 1

1

您可以使用来计算中点shift以获取连续行的时间差，然后除以 2 即可Start Time。然后，只需shift(-1)一行即可获得End Time：

df['Start Time'] = (df['Datetime'] + (df['Datetime'].shift(1) - df['Datetime']) / 2).fillna(df['Datetime'])
df['End Time'] = (df['Start Time'].shift(-1)).fillna(df['Datetime'])
df
Out[1]: 
              Datetime          Start Time            End Time
0  2020-12-01 00:00:00 2020-12-01 00:00:00 2020-12-01 00:30:00
1  2020-12-01 01:00:00 2020-12-01 00:30:00 2020-12-01 01:30:00
2  2020-12-01 02:00:00 2020-12-01 01:30:00 2020-12-01 02:30:00
3  2020-12-01 03:00:00 2020-12-01 02:30:00 2020-12-01 03:30:00
4  2020-12-01 04:00:00 2020-12-01 03:30:00 2020-12-01 04:30:00
5  2020-12-01 05:00:00 2020-12-01 04:30:00 2020-12-01 05:30:00
6  2020-12-01 06:00:00 2020-12-01 05:30:00 2020-12-01 07:30:00
7  2020-12-01 09:00:00 2020-12-01 07:30:00 2020-12-01 10:30:00
8  2020-12-01 12:00:00 2020-12-01 10:30:00 2020-12-01 15:00:00
9  2020-12-01 18:00:00 2020-12-01 15:00:00 2020-12-01 21:00:00
10 2020-12-02 00:00:00 2020-12-01 21:00:00 2020-12-02 00:00:00
于 2020-12-02T01:27:29.757 回答