我有两个类BaseNode
,BaseEdge
我可以使用connect
方法通过这些类中的边缘连接两个节点。
代码
这是我的BaseNode
:
class BaseNode:
def __init__(self,edges=[],value=None,edges_limit=math.inf):
self.edges = edges
self.value = value
self.limit = edges_limit
self.edge_class = BaseEdge
self.adjs = []
def get_adjacents(self):
if not self.edges:
return []
for edge in self.edges :
self.adjs.append(edge.n2)
return self.adjs
def get_edges(self):
return self.edges
def connect(self,other):
"""
connect two nodes by connecting an edge between them
"""
if not isinstance(other,self.__class__):
raise ValueError(f'Node should be type of {self.__class__.__name__}')
if len(self.edges) == self.limit :
raise MaximumEdgeReached(f'maximum edge reached the limit is {self.limit} ')
e = BaseEdge()
e.set_nodes(self,other)
self.edges.append(e)
和BaseEdge
类:
class BaseEdge:
def __init__(self):
self.n1 = None
self.n2 = None
self.node_class = BaseNode
def get_nodes(self):
return (self.n1,self.n2,)
def set_nodes(self,n1,n2):
a = isinstance(n1,self.node_class)
b = isinstance(n2,self.node_class)
if not a and b :
raise ValueError(f'nodes of this edge should be {self.node_class}')
self.n1 = n1
self.n2 = n2
def connect(self,n1=None,n2=None):
if not self.n1 and self.n2 :
self.set_nodes(n1,n2)
self.n1.edges.append(self)
self.n2.edges.append(self)
我试过什么?
我试图连接两者的点头BaseNode
并BaseEdge
查看结果。节点应该具有相同的边缘,但发生了 2 个问题:
edges
的属性,n1
它们n2
是第一个节点和第二个节点,有 2 个实例,e
其中是边!但edges
应该有 1 个实例BaseEdge
- 当我创建新对象时
BaseNode
,该edges
属性对它们具有相同的值!.
>>> n1 = BaseNode()
>>> n2 = BaseNode()
>>> e = BaseEdge()
>>> e.set_nodes(n1,n2)
>>> e.connect()
>>> n2.edges
[<__main__.BaseEdge object at 0x0000000003282BA8>, <__main__.BaseEdge object at 0x0000000003282BA8>]
>>> n1.edges
[<__main__.BaseEdge object at 0x0000000003282BA8>, <__main__.BaseEdge object at 0x0000000003282BA8>]
>>> n3 = BaseNode() #initializing new oject
>>> n3.edges
[<__main__.BaseEdge object at 0x0000000003282BA8>, <__main__.BaseEdge object at 0x0000000003282BA8>]
注意:当我使用类connect
的方法时BaseNode
。它也有同样的问题。
BaseNode
类就像一个单态类。它不应该是!请帮我解决这个问题。