json - Mysql JSON 更新键值

Question

我有一张像这样的桌子：

CREATE TABLE `campus_tb` (
 `campus_id` int(11) NOT NULL AUTO_INCREMENT,
 `campus_dataJSON` longtext CHARACTER SET utf8mb4 COLLATE utf8mb4_bin NOT NULL CHECK (json_valid(`campus_dataJSON`)),
 PRIMARY KEY (`campus_id`)
) ENGINE=InnoDB AUTO_INCREMENT=2 DEFAULT CHARSET=utf8mb4 COLLATE=utf8mb4_unicode_ci

INSERT INTO `campus_tb`( `campus_dataJSON`) VALUES ( '[
                          {"id":"100","name":"James","age":"17","course":"IT"},
                          {"id":"101","name":"Eric","age":"19","course":"CS"},
                          {"id":"102","name":"Julie","age":"21"}]')




+--------------------+-----------------------------------------------------------+
| campus_id          |  campus_dataJSON                                          | 
+--------------------+-----------------------------------------------------------+
| 1                  |  [
                     |     {"id":"100","name":"James","age":"17","course":"IT"},
                     |     {"id":"101","name":"Eric","age":"19","course":"CS"},
                     |     {"id":"102","name":"Julie","age":"21"}
                     |
                     |  ] 
----------------------------------------------------------------------------------  
| 2                  |  [
                     |     {"id":"34","name":"Mimi","age":"18","course":"IT"},
                     |     {"id":"35","name":"Jose","age":"20","course":"CS"},
                     |     {"id":"36","name":"Ken","age":"24"}
                     |
                     |  ]
----------------------------------------------------------------------------------  

我正在使用 MariaDB 10.4

1. MySql 查询 UPDATE the details for Julie ofcampus_id = 1添加“课程”让她变成这样：

   {"id":"102","name":"Julie","age":"21","course":"MASCOM"},

2. Mysql Query to UPDATE从“Eric”到“Erick”，末尾带有“k”

到目前为止我已经尝试过：

UPDATE `campus_tb` 
SET `campus_dataJSON` = JSON_SET (`campus_dataJSON`, TRIM( '"' FROM JSON_SEARCH(`campus_dataJSON`,'one','Julie')),'MASCOM') 
WHERE 
    `campus_id` = 1 AND 
    JSON_EXTRACT(`campus_dataJSON`,'$.id') = '102';

这返回0 rows affected......我已经大量搜索。

Answer 1

基本上你应该使用JSON_SET函数。例如，第一个问题可以通过以下方式解决：

update campus 
 set campus_data = json_set(
   campus_data, '$[2].course', 'MASCOM')
 where campus_id = 1;

在SQLize.online上测试

如果您不知道 JSON 路径，您可以使用JSON_SEARCH和JSON_UNQUOTE ，例如：

update campus 
 set campus_data = json_set(
   campus_data, 
   json_unquote(json_search(campus_data, 'one', 'Eric')), 
   'Erick'
 )
 where campus_id = 1;
 

在这里提琴