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您好我正在尝试在 php 中创建一个上传表单。包含、上传输入、文本输入（上传文件的名称）和提交按钮。但是我不太了解，php,所以我不知道如何实际链接我输入的内容在<input type="text"/>上传时成为文件的名称。如果有人可以帮忙？谢谢。

这是我的代码：

<!DOCTYPE html>
<html>
<head>
  <title>Tu peux uploader ici ta video.</title>
</head>
<body>
  <form enctype="multipart/form-data" action="upload.php" method="POST">
    <p>Upload your file</p>
    <input type="file" name="uploaded_file"></input><br />
    <input type="text" name="file-name"></input><br />  <!-- [ASK]: How to make this the file name of the uploaded file -->
    <input type="submit" value="Upload"></input>
  </form>
</body>
</html>
<?PHP
  if(!empty($_FILES['uploaded_file']))
  {
    $path = "uploads/";
    $path = $path . basename( $_FILES['uploaded_file']['name']);
​
    if(move_uploaded_file($_FILES['uploaded_file']['tmp_name'], $path)) {
      echo "The file ".  basename( $_FILES['uploaded_file']['name']). 
      " has been uploaded";
    } else{
        echo "There was an error uploading the file, please try again!";
    }
  }
?>
4

1 回答 1

1

move_uploaded_file ( string $filename , string $destination ) 采用 filename ，它是上传文件的文件名，destination 是移动文件的目标。注意目标目录必须存在；move_uploaded_file() 不会自动创建它。所以现在让我们来取名字......

  • $_FILES['uploaded_file']['tmp_name'] 为您提供上传文件存储在服务器上的文件的临时文件名，例如。C:\Users\USER\AppData\Local\Temp\phpD3C.tmp 而
  • $_FILES['uploaded_file']['name'] 为您提供提取扩展名所需的实际名称，例如。我的文件.jpg
  • 要链接您在 上键入的内容，首先通过 $_POST["file-name"] 获取它，然后与扩展名连接。使用 pathinfo 检索原始扩展名。

将您的代码更改为...

 <!DOCTYPE html>
<html>
<head>
  <title>Tu peux uploader ici ta video.</title>
</head>
<body>
  <form enctype="multipart/form-data" action="upload.php" method="POST">
    <p>Upload your file</p>
    <input type="file" name="uploaded_file"></input><br />
    <input type="text" name="file-name"></input><br />  <!-- [ASK]: How to make this the file name of the uploaded file -->
    <input type="submit" value="Upload"></input>
  </form>
</body>
</html>

<?php
if ($_SERVER["REQUEST_METHOD"] == "POST") {

  if(!empty($_FILES['uploaded_file']))
  {
    $file_parts = pathinfo(basename( $_FILES['uploaded_file']['name'])); //access the actual name instead of tmp_name
    //just pick the extension of the file_parts and concatenate it to your path
    $path = 'images/';
    $path = $path . $_POST["file-name"] . "." . $file_parts['extension'] ;
    if(move_uploaded_file($_FILES['uploaded_file']['tmp_name'], $path)) {
      echo "The file ". basename($path) ." has been uploaded";
    } else{
        echo "There was an error uploading the file, please try again!";
    }
  }
}
?>

这应该会为您提供所需的名称。因此，如果您上传文件 dog.php 并且在文本字段中有牛，则结果名称应该是 cow.php。

结果： 在此处输入图像描述

于 2020-11-24T13:06:08.610 回答