0

我的代码是：

import xmpp

jabberid = "admin@mydomain.com"
password = "password"
receiver = "admin@mydomain.com"
message  = "hello world"

jid = xmpp.protocol.JID(jabberid)
connection = xmpp.Client(server=jid.getDomain())
connection.connect()
connection.auth(user=jid.getNode(), password=password,resource=jid.getResource())

我收到此错误：

 File "/home/eduardo/.local/share/virtualenvs/xmpp-sv-KIKvfzDF/lib/python3.6/site-packages/flask/app.py", line 1950, in full_dispatch_request
    rv = self.dispatch_request()
  File "/home/eduardo/.local/share/virtualenvs/xmpp-sv-KIKvfzDF/lib/python3.6/site-packages/flask/app.py", line 1936, in dispatch_request
    return self.view_functions[rule.endpoint](**req.view_args)
  File "/home/eduardo/Desktop/adiconf/xmpp-sv/api/main/user/routes.py", line 33, in add
    connection.auth(user=str(jid.getNode()), password=str(password), resource=str(jid.getResource()))
  File "/home/eduardo/.local/share/virtualenvs/xmpp-sv-KIKvfzDF/lib/python3.6/site-packages/xmpp/client.py", line 228, in auth
    while self.SASL.startsasl=='in-process' and self.Process(1): pass
  File "/home/eduardo/.local/share/virtualenvs/xmpp-sv-KIKvfzDF/lib/python3.6/site-packages/xmpp/dispatcher.py", line 126, in Process
    raise _pendingException[0](_pendingException[1]).with_traceback(_pendingException[2])
  File "/home/eduardo/.local/share/virtualenvs/xmpp-sv-KIKvfzDF/lib/python3.6/site-packages/xmpp/dispatcher.py", line 304, in dispatch
    handler['func'](session,stanza)
  File "/home/eduardo/.local/share/virtualenvs/xmpp-sv-KIKvfzDF/lib/python3.6/site-packages/xmpp/auth.py", line 179, in SASLHandler
    self.DEBUG('Got challenge:'+data,'ok')
TypeError: must be str, not bytes

我正在使用 xmpppy 模块，但我不知道为什么？因为我传递给 connection.auth 的参数都是字符串

4

1 回答 1

0

您必须解码 lib 中“auth”文件中的数据。这条线必须看起来像那样。

数据=base64.b64decode(incoming_data).decode()

于 2021-05-24T20:45:10.283 回答