2

我有一个使用 knex 进行迁移的应用程序。早些时候有人使用knex.raw这样的方法在一列上创建了唯一索引:

const createProgrammeTable = knex => knex.raw(`
  CREATE TABLE programme (
    id             serial PRIMARY KEY,
    date           date NOT NULL,
    published      date,
    description    text
  );
  CREATE UNIQUE INDEX programme_date_index ON programme(date);
`)

使用 psql 打印出数据库时,我得到以下信息:

server=# \d programme;
                              Table "public.programme"
  Column   |  Type   | Collation | Nullable |                Default
-----------+---------+-----------+----------+---------------------------------------
 id        | integer |           | not null | nextval('programme_id_seq'::regclass)
 date      | date    |           | not null |
 published | boolean |           | not null |
Indexes:
    "programme_pkey" PRIMARY KEY, btree (id)
    "programme_date_index" UNIQUE, btree (date)

现在我想删除唯一约束,但我不确定如何。我读过我可以这样做:

ALTER TABLE programme DROP INDEX programme_date_index;

但是这样做会knex.raw产生这个错误:

migration failed with error: ALTER TABLE programme DROP INDEX programme_date_index - syntax error at or near "programme_date_index"
error: ALTER TABLE programme DROP INDEX programme_date_index - syntax error at or near "programme_date_index"
    at Connection.parseE (/Users/my-path/node_modules/pg/lib/connection.js:555:11)
    at Connection.parseMessage (/Users/my-path/node_modules/pg/lib/connection.js:380:19)
    at Socket.<anonymous> (/Users/my-path/node_modules/pg/lib/connection.js:120:22)
    at Socket.emit (events.js:198:13)
    at addChunk (_stream_readable.js:288:12)
    at readableAddChunk (_stream_readable.js:269:11)
    at Socket.Readable.push (_stream_readable.js:224:10)
    at TCP.onStreamRead [as onread] (internal/stream_base_commons.js:94:17)
error Command failed with exit code 1.

我也尝试过像这样使用dropUnique

exports.up = function(knex, Promise) {
  return knex.schema.alterTable("programme", function(t) {
    t.dropUnique("date", "programme_date_index")
  })
}

这给出了以下错误:

migration failed with error: alter table "programme" drop constraint "programme_date_index" - constraint "programme_date_index" of relation "programme" does not exist

版本

Knex CLI 版本:0.20.15 / Knex 本地版本:0.20.15

server=# select version();
                                                     version
------------------------------------------------------------------------------------------------------------------
 PostgreSQL 12.2 (Debian 12.2-2.pgdg100+1) on x86_64-pc-linux-gnu, compiled by gcc (Debian 8.3.0-6) 8.3.0, 64-bit

有人可以帮我/把我推向正确的方向吗?

4

3 回答 3

2

将 Knex 与 Posgresql 一起使用,我刚刚以这种方式解决了类似的问题:

import * as Knex from "knex";

export async function up(knex: Knex): Promise<void> {
    return await knex.schema
        .withSchema('public')
        .table('elements', (table) => {
            table.dropUnique(null, 'elements_name_unique');
        });
}

export async function down(knex: Knex): Promise<void> {
    return knex.schema.table('elements', (table) => {
        table.unique(['name']);
    });
}

打字稿约束让它变得很奇怪,我不得不用参数作弊。

我使用 Knex CLI 版本:0.21.17 / Knex 本地版本:0.21.18

于 2021-02-26T15:28:32.557 回答
0
export async function down(db: Knex): Promise<void> {
    db.schema.alterTable('tablename', function (t) {
        t.dropUnique([], 'indexname')
    })
}

如果您使用打字稿来删除索引。

于 2021-06-16T10:56:03.643 回答
-1

包裹

"knex": "^0.95.8",

这是我通常做的:

exports.up = function (knex) {
  return knex.schema.alterTable('users', function (table) {
    table.dropUnique('user_id');
  });
};
exports.down = function (knex) {
  return knex.schema.alterTable('users', function (table) {
    table.unique('user_id');
  });
};

但是我们遇到了这个有趣的问题,我们之前更改了列名并重命名了该列。由于某种原因,数据库仍然有一个约束,旧的列名是唯一的。所以我们必须先删除旧的约束。要记住的事情!

于 2021-07-30T16:26:26.077 回答