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就像在这个文件中规则中的“最多”关键字一样:

horn1.smt2(来自 Z3 github 存储库示例/python/data)

(declare-rel Goal (Bool Bool Bool Bool Bool Bool Bool Bool Bool Bool Bool Bool))
(declare-rel Invariant (Bool Bool Bool Bool Bool Bool Bool Bool Bool Bool Bool Bool))
(declare-var A Bool)
(declare-var B Bool)
(declare-var C Bool)
(declare-var D Bool)
(declare-var E Bool)
(declare-var F Bool)
(declare-var G Bool)
(declare-var H Bool)
(declare-var I Bool)
(declare-var J Bool)
(declare-var K Bool)
(declare-var L Bool)
(declare-var M Bool)
(declare-var N Bool)
(declare-var O Bool)
(declare-var P Bool)
(declare-var Q Bool)
(declare-var R Bool)
(declare-var S Bool)
(declare-var T Bool)
(declare-var U Bool)
(declare-var V Bool)
(declare-var W Bool)
(declare-var X Bool)
(rule (=> (not (or L K J I H G F E D C B A)) (Invariant L K J I H G F E D C B A)))
(rule (let ((a!1 (and (Invariant X W V U T S R Q P O N M)
                (=> (not (and true)) (not F))
                (=> (not (and true)) (not E))
                (=> (not (and W)) (not D))
                (=> (not (and W)) (not C))
                (=> (not (and U)) (not B))
                (=> (not (and U)) (not A))
                (= L (xor F X))
                (= K (xor E W))
                (= J (xor D V))
                (= I (xor C U))
                (= H (xor B T))
                (= G (xor A S))
                (=> D (not E))
                (=> C (not E))
                (=> B (not C))
                (=> A (not C))
                ((_ at-most 5) L K J I H G))))
  (=> a!1 (Invariant L K J I H G F E D C B A))))
(rule (=> (and (Invariant L K J I H G F E D C B A) L (not K) J (not I) H G)
    (Goal L K J I H G F E D C B A)))
(query Goal)

似乎关键字“最多”的含义是六个字面量(LKJIHG)中只有五个字面量可以同时为真,或者它意味着什么,我想不通。如果有任何好人可以帮助我,我真的很感激。

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1 回答 1

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这些是伪布尔函数,有关详细信息,请参阅此答案:K-out-of-N constraint in Z3Py

基本上:

  • at-most: 最多只有这么多是真的
  • at-least: 至少有这么多是真的
  • pble: 最多这么多,加权
  • pbge: 至少有这么多,加权
  • pbeq: 就是这么多,加权

加权版本本质上是布尔值的乘数,并采用整数的常量列表。

请注意,这些是 z3 特定的,实际上并未在 SMTLib 中定义。当然,可能还有其他求解器也支持它。

于 2020-11-15T06:50:08.337 回答