1

我一直在尝试解决这个问题,但无法真正将它与任何解决方案联系起来。我有以下数据集:

[
  {"name": "sam", "hobbies": ["Books", "Music", "Gym"]},
  {"name": "Steve", "hobbies": ["Books", "Swimming"]},
  {"name": "Alex", "hobbies": ["Gym", "Music"]}
]

我正在尝试生成可以按爱好组合人们的输出数据集。所以输出应该是这样的:

[
  {"names": ["sam", "Steve"], "hobbies": ["Books"]},
  {"names": ["sam", "Alex"], "hobbies": ["Music", "Gym"]},
  {"names": ["Steve"], "hobbies": ["Swimming"]}
]

它是一个大型数据集,所以我尝试使用 Spark。

我尝试过的事情:

  • 最初我试图看看它是否是一个图形问题,我可以使用强连接组件之类的东西,但看起来这并不能解决问题。

  • 每个输出行看起来像一个二分图,但我也找不到生成它的方法。

  • 另一种方法是聚类,但我认为它不是确定性的。如果我错了,请告诉我。我对它不太熟悉。

如果我在这里遗漏了一些明显的东西,请告诉我。谢谢。

4

1 回答 1

1

检查下面的代码。

scala> df.show(false)
+-------------------+-----+
|hobbies            |name |
+-------------------+-----+
|[Books, Music, Gym]|sam  |
|[Books, Swimming]  |Steve|
|[Gym, Music]       |Alex |
+-------------------+-----+

使用groupBy&collect_list

  1. 分组hobbies和收集列表names
  2. 分组names和收集列表hobbies
scala> :paste
// Entering paste mode (ctrl-D to finish)

df
.withColumn("hobbies",explode($"hobbies"))
.groupBy($"hobbies").agg(collect_list($"name").as("names")) // For Hobbies List
.groupBy($"name").agg(collect_list($"hobbies").as("hobbies")) // For Name List
.select(collect_list(to_json(struct($"hobbies",$"names"))).as("data")) // Final Json Output
.show(false)


// Exiting paste mode, now interpreting.

+--------------------------------------------------------------------------------------------------------------------------------------------+
|data                                                                                                                                        |
+--------------------------------------------------------------------------------------------------------------------------------------------+
|[{"hobbies":["Swimming"],"names":["Steve"]}, {"hobbies":["Books"],"names":["sam","Steve"]}, {"hobbies":["Music","Gym"],"names":["sam","Alex"]}]|
+--------------------------------------------------------------------------------------------------------------------------------------------+

格式化输出

[
  { "hobbies": ["Swimming"],"names": ["Steve"]},
  {"hobbies": ["Books"],"names": ["sam","Steve"]},
  {"hobbies": ["Music","Gym"],"names": ["sam","Alex"]}
]
于 2020-11-13T17:42:56.743 回答