如何在颤振中获取实时位置的坐标?我想获取实时位置坐标。可以做些什么来得到这个?我在颤振中导入了位置包,但我只想获取实时位置的坐标。
2 回答
1
首先你需要一个定位插件。 https://pub.dev/packages/location。我还建议使用 Provider 插件并创建模型文件。会更容易管理。此外,您必须检查设备的权限状态。您将通过链接获得您想了解的所有信息
class MyHomePage extends StatefulWidget {
@override
_MyHomePageState createState() => _MyHomePageState();
}
class _MyHomePageState extends State<MyHomePage> {
Location _location = Location();
LocationData currentLocation;
@override
void initState() {
location = new Location();
location.onLocationChanged.listen((LocationData cLoc) {
currentLocation = cLoc;
});
super.initState();
}
@override
Widget build(BuildContext context) {
return Center(
child: Text(
'Location: Lat${currentLocation.latitude}, Long: ${currentLocation.longitude}'),);}}
于 2020-11-13T13:25:39.100 回答
0
Location location = new Location();
bool _serviceEnabled;
PermissionStatus _permissionGranted;
LocationData _locationData;
_serviceEnabled = await location.serviceEnabled();
if (!_serviceEnabled) {
_serviceEnabled = await location.requestService();
if (!_serviceEnabled) {
return;
}
}
_permissionGranted = await location.hasPermission();
if (_permissionGranted == PermissionStatus.denied) {
_permissionGranted = await location.requestPermission();
if (_permissionGranted != PermissionStatus.granted) {
return;
}
}
location.onLocationChanged.listen((LocationData currentLocation) {
// Use current location
});
于 2020-11-13T08:18:34.483 回答