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我很混乱。阅读此线程后,我尝试将 List 写入内部存储onPause(),然后读取 List onResume()。仅出于测试目的,我正在尝试编写一个简单的字符串,如示例所示。我有这个要写的:

    String FILENAME = "hello_file";
    String string = "hello world!";

    FileOutputStream fos = null;
    try {
        fos = openFileOutput(FILENAME, Context. MODE_WORLD_READABLE);
    } catch (FileNotFoundException e1) {
        // TODO Auto-generated catch block
        e1.printStackTrace();
    }
    try {
        fos.write(string.getBytes());
    } catch (IOException e1) {
        // TODO Auto-generated catch block
        e1.printStackTrace();
    }
    try {
        fos.close();
    } catch (IOException e1) {
        // TODO Auto-generated catch block
        e1.printStackTrace();
    }

我试图onResume()通过调用来阅读它:

    try {
            resultText01.setText(readFile("hello_file"));
        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
            resultText01.setText("exception, what went wrong? why doesn't this text say hello world!?");
        }

当然哪个使用这个:

private static String readFile(String path) throws IOException {
      FileInputStream stream = new FileInputStream(new File(path));
      try {
        FileChannel fc = stream.getChannel();
        MappedByteBuffer bb = fc.map(FileChannel.MapMode.READ_ONLY, 0, fc.size());
        /* Instead of using default, pass in a decoder. */
        return Charset.defaultCharset().decode(bb).toString();
      }
      finally {
        stream.close();
      }
    }

由于某种原因,resultText01.setText(...)没有设置为"hello world!",而是调用了 catch 异常。如果我的术语不正确,我很抱歉,我是新手。感谢您的任何指示。

4

1 回答 1

2

而不是您的方法中的以下内容readFile(...)...

FileInputStream stream = new FileInputStream(new File(path));

尝试...

FileInputStream stream = openFileInput(path);
于 2011-06-25T22:02:52.000 回答