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我对颤振完全陌生,我正在使用 web view 小部件,但是每当我按下它时,它就会退出应用程序。按下后退按钮时如何返回上一页?

这是我的代码片段

import 'package:flutter/material.dart';
import 'package:webview_flutter/webview_flutter.dart';
void main() => runApp(MyApp());
WebViewController controllerGlobal;

Future<bool> _exitApp(BuildContext context) async {
  if (await controllerGlobal.canGoBack()) {
    print("onwill goback");
    controllerGlobal.goBack();
    return Future.value(true);
  } else {
    Scaffold.of(context).showSnackBar(
      const SnackBar(content: Text("No back history item")),
    );
    return Future.value(false);
  }
}
class MyApp extends StatelessWidget {
  @override
  Widget build(BuildContext context) {
    return MaterialApp(
      debugShowCheckedModeBanner: false,
      title: 'TRAVMAKS',
      home: WillPopScope(
        onWillPop: () => _exitApp(context),
        child:Scaffold(
              body: Container(
                    margin: const EdgeInsets.only(top: 52.0),
                    child: Container(
                            margin: const EdgeInsets.only(top: 0.0),
                            child: WebView(
                                        initialUrl: 'https://www.google.com',
                                        javascriptMode: JavascriptMode.unrestricted,
                        )
              )
        )
    )
    )
    );

  }
}
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1 回答 1

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true导航回您的WebView. 如果您返回truein onWillPop,Flutter 会弹出该路由,如果它是您的根路由,则应用程序将退出。您可能也想在那里返回 false 。

https://api.flutter.dev/flutter/widgets/WillPopScope/onWillPop.html

于 2020-11-06T10:59:38.803 回答