1

我有桌子products

+----------+-----------+----------+---------+
|family_id |shopper_id |product_id|quantity |
+----------+-----------+----------+---------+
|A         |1          |Kit Kat   |10       |
|A         |1          |Kit Kat   |5        |
|A         |1          |Snickers  |9        |
|A         |2          |Kit Kat   |7        |
|B         |3          |Kit Kat   |2        |
+----------+---------- +----------+---------+

对于每种产品,我想计算 2 个总数:

  • 每个购物者的总数量
  • 每个家庭的总量。同一家庭中所有购物者的总数量。

决赛桌应如下所示:

+----------+----------+-------------------------+-----------------------+
|shopper_id|product_id|total_quantity_shopper   |total_quantity_family  |
+----------+----------+-------------------------+-----------------------+
|1         |Kit Kat   | 15                      | 22                    |
|1         |Snickers  | 9                       | 9                     |
|2         |Kit Kat   | 7                       | 22                    |
|3         |Kit Kat   | 2                       | 2                     |
+----------+----------+-------------------------|-----------------------|

这是我的查询:

SELECT
    distinct shopper_id,
    product_id,
    sum(quantity) OVER (PARTITION BY shopper_id, product_id) as total_quantity_shopper,
    sum(quantity) OVER (PARTITION BY family_id, product_id) as total_quantity_family
FROM
    products;

但是看查询计划,看起来效率很低(我认为)。如何改进上面的查询?

4

1 回答 1

3

我认为家庭是购物者的等级制度。所以,我建议group by和窗口功能:

select family_id, shopper_id, product_id,
       sum(quantity) as total_quantity_shopper,
       sum(sum(quantity)) over (partition by family_id, product_id) as total_quantity_family
from products
group by family_id, shopper_id, product_id
于 2020-11-04T21:52:11.023 回答