1

我想进行过采样，以便我在数据集中的每个组中平衡我的二进制因变量。

所以我的数据看起来像这样：

library(dplyr)
library(purrr)
library(tidyr)
seed(123)

# example data
(data <- tibble(
  country = c("France", "France", "France", 
              "UK", "UK", "UK", "UK", "UK", "UK"),
  YES = c(0, 0, 1, 
          0, 0, 0, 0, 1, 1),
  X = rnorm(9, 0 ,1)
))

# A tibble: 9 x 3
  country   YES       X
  <chr>   <dbl>   <dbl>
1 France      0 -1.12  
2 France      0 -0.200 
3 France      1  0.781 
4 UK          0  0.100 
5 UK          0  0.0997
6 UK          0 -0.380 
7 UK          0 -0.0160
8 UK          1 -0.0265
9 UK          1  0.860

我试图通过过采样在法国和英国实现 YES 的平衡。在法国，我希望有 4 个观察结果，而在英国，我希望有 8 个观察结果，以便一个随机样本看起来像这样）：

# A tibble: 12 x 3
  country   YES       X
  <chr>   <dbl>   <dbl>
1 France      0 -1.12  
2 France      0 -0.200 
3 France      1  0.781 
3 France      1  0.781 
4 UK          0  0.100 
5 UK          0  0.0997
6 UK          0 -0.380 
7 UK          0 -0.0160
8 UK          1 -0.0265
9 UK          1  0.860
8 UK          1 -0.0265
8 UK          1 -0.0265

我的方法是这样的：

# oversample 1's within each country
(n_data <- data %>%
  group_by(country) %>%
  nest(.key = "original") %>%
  mutate(os = map(original, ~ group_by(., YES))) %>%
  mutate(os = map(os, ~ slice_sample(., replace = TRUE, prop = 1))))

# A tibble: 2 x 3
# Groups:   country [2]
  country original         os              
  <chr>   <list>           <list>          
1 France  <tibble [3 x 2]> <tibble [3 x 2]>
2 UK      <tibble [6 x 2]> <tibble [6 x 2]>
Warning message:
`.key` is deprecated

所以在操作系统中，尺寸应该是 4 x 2 和 8 x 2。有人知道怎么做吗？

4

1 回答 1

0

这似乎过于复杂，但每个单独的步骤似乎都清晰而稳健：

data %>% 
  count(country, YES) %>%
  group_by(country) %>%
  ## Figure out how many additional rows are needed
  mutate(
    goal_rows = max(n),
    extra_rows = goal_rows - n
  ) %>%
  select(country, YES, extra_rows) %>%
  ## Keep only the country/YES combinations that need extra rows
  filter(extra_rows > 0) %>%
  ## Join back to original data
  left_join(data, by = c("country", "YES")) %>%
  group_by(country) %>%
  ## Randomly keep the appropriate number of rows
  mutate(rand = rank(runif(n()))) %>%
  filter(rand <= extra_rows) %>%
  select(-extra_rows, -rand) %>%
  ## Combine oversampled rows with original data
  bind_rows(data) %>%
  arrange(country, YES)
# # A tibble: 12 x 3
# # Groups:   country [2]
#    country   YES       X
#    <chr>   <dbl>   <dbl>
#  1 France      0  1.88  
#  2 France      0 -0.0793
#  3 France      1  0.812 
#  4 France      1  0.812 
#  5 UK          0 -1.66  
#  6 UK          0 -0.797 
#  7 UK          0  0.639 
#  8 UK          0 -0.141 
#  9 UK          1 -0.207 
# 10 UK          1  1.30  
# 11 UK          1 -0.207 
# 12 UK          1  1.30
于 2020-10-28T18:28:05.140 回答