1

我有一个工人的数据类,

data class Worker(val id: Int, val name:String, val gender :String, val age :Int, val tel:String,val email:String)

和工人名单

List<Worker> = listOf(workerA, workerB)

我想写一个函数来更新 Worker 的数据,例如:

updateWorkerData(1, age, 28)

//'type' refer to name, gender, age ..
//'value' refer AA, Female, 27 ..
fun updateWorkerData(id: Int, type: Any, value: Any) {
  val workers = getListOfWorker()
  workers.forEach {
  if (it.id == id) {
   //here is where I stuck    
  }    
}
}

我被困在如何将类型引用到数据类 Worker 中的值上。需要一些有关如何更新 Worker 数据的指南。谢谢。

4

3 回答 3

5

您的数据类应该具有可变属性,以便可以更改它们:

data class Worker(val id: Int, var name: String, var gender: String, var age: Int, var tel: String, var email: String)

然后您可以将 KProperty 传递给可以更改该属性的函数:

fun <T> updateWorkerData(id: Int, property: KMutableProperty1<Worker, T>, value: T) {
    val workers = getListOfWorker()
    workers.forEach {
        if (it.id == id) {
            property.set(it, value)
        }
    }
}

updateWorkerData(1, Worker::age, 28)
于 2020-10-28T07:35:05.897 回答
2

我更喜欢使用不变性而不是对数据类使用可变字段。

一个简单的解决方案如下:

fun List<Worker>.updateWorkerDataAge(id: Int, age: Int): List<Worker> =
        this.map { worker -> if (worker.id == id) worker.copy(age = age) else worker }

你可以使用它:

val newWorkerList = workerList.updateWorkerDataAge(2, 99)
于 2021-10-16T08:41:34.587 回答
1

Animesh 的回答是正确的,我只是想指出,使用MapWorkers (其中关键是工人 ID)可能更简单,直接编辑工人,而不是做聪明(且难以理解)的事情反射:

val workers: Map<Int, Worker> = listOf(
    Worker(1, "a", "a", 1, "a", "a"),
    Worker(2, "b", "b", 2, "b", "b"),
    Worker(3, "c", "c", 3, "c", "c"),
).map { it.id to it }.toMap()

// Worker 1 changes name
workers.getValue(1).name = "Slartibartfast"

// Worker 2 gets older
workers.getValue(2).age += 1

// Worker 3 changes email
workers.getValue(3).email = "newemail@example.com"
于 2020-10-28T15:03:56.590 回答