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我想向用户展示当地的兴趣点。由于这不是我的应用程序的主要目标，我希望找到一个相当简单的解决方案，例如将用户发送到 Google Places 或任何其他基于位置的应用程序。

有没有办法做到这一点？如果答案是否定的，我该怎么做？也许使用一些API？

谢谢

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2 回答 2

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您可以使用此处记录的 android 位置和地图 api 。如果没有，您可以随时调用地图意图，但您必须确保在使用之前安装了谷歌地图。这是使用此处Location链接的 android 开发页面中的 api的示例：

// Acquire a reference to the system Location Manager
LocationManager locationManager = (LocationManager) this.getSystemService(Context.LOCATION_SERVICE);

// Define a listener that responds to location updates
LocationListener locationListener = new LocationListener() {
    public void onLocationChanged(Location location) {
      // Called when a new location is found by the network location provider.
      makeUseOfNewLocation(location);
    }

    public void onStatusChanged(String provider, int status, Bundle extras) {}

    public void onProviderEnabled(String provider) {}

    public void onProviderDisabled(String provider) {}
  };

// Register the listener with the Location Manager to receive location updates
locationManager.requestLocationUpdates(LocationManager.NETWORK_PROVIDER, 0, 0, locationListener);

现在在此处使用 google API 注册您的应用程序。获得 API 密钥后，您可以使用 http 请求访问https://maps.googleapis.com/maps/api/place/search/json?location=&radius=&types=&name=&sensor=&key=YOUR_API_KEY.

您可以在此处从 google maps api 站点找到每个参数的定义，但这是一个小列表：

location (required) — The latitude/longitude around which to retrieve Place information. This must be provided as a google.maps.LatLng object.
radius (required) — The distance (in meters) within which to return Place results. The recommended best practice is to set radius based on the accuracy of the location signal as given by the location sensor. Note that setting a radius biases results to the indicated area, but may not fully restrict results to the specified area.
types (optional) — Restricts the results to Places matching at least one of the specified types. Types should be separated with a pipe symbol (type1|type2|etc). See the list of supported types.
language (optional) — The language code, indicating in which language the results should be returned, if possible. See the list of supported languages and their codes. Note that we often update supported languages so this list may not be exhaustive.
name (optional) — A term to be matched against the names of Places. Results will be restricted to those containing the passed name value. When a name is included, the area being searched may be broadened, to ensure a suitable number of results.
sensor (required) — Indicates whether or not the Place request came from a device using a location sensor (e.g. a GPS) to determine the location sent in this request. This value must be either true or false.
key (required) — Your application's API key. This key identifies your application for purposes of quota management and so that Places added from your application are made immediately available to your app. Visit the APIs Console to create an API Project and obtain your key.

这是 android 中的一个快速 HTTP 请求示例：

HttpGet myGet = new HttpGet("https://maps.googleapis.com/maps/api/place/search/json?location=&radius=&types=&name=&sensor=&key=YOUR_API_KEY");

获得返回结果后，您可以使用任何 json 库（例如 google-gson）从此处解析响应。

瑞安

于 2011-06-23T14:18:18.387 回答
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您的问题尚不清楚，但从您的问题中，我可以知道您想显示用户感兴趣的位置，如果我错了，请纠正我。

如果你想同样的话

1）您需要该点的纬度和经度，因为您可以使用任何API，您可以从您的网络服务中获取这些点

2）获得纬度和经度列表后，您可以使用逐项叠加显示在地图上

于 2011-06-23T14:44:29.603 回答