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如何编写一个程序来读取整数并显示二进制数而不使用循环,只使用二进制运算符?(仅限基本功能)

 #include<stdio.h>     
 #include<stdint.h>     
 #include<math.h>        
 int main()       
 {uint8_t a;      
 scanf("%hhd", &a);   
 //i have read the integer, but I don't know how to go on  
 return 0;      
 }      
4

1 回答 1

0

不使用循环显示二进制数,仅使用二元运算符:

#include<stdio.h>     
#include<stdint.h>     
#include<math.h>        
int main()       
{
  int a;      
  scanf("%u", &a);

  printf("Number: 0x%X\n", a);
  
  printf("%d", ((a & 0x80) >> 7));
  printf("%d", ((a & 0x40) >> 6));
  printf("%d", ((a & 0x20) >> 5));
  printf("%d", ((a & 0x10) >> 4));
  printf("%d", ((a & 0x08) >> 3));
  printf("%d", ((a & 0x04) >> 2));
  printf("%d", ((a & 0x02) >> 1));
  printf("%d", ((a & 0x01) >> 0));

  printf("\n");
  
  return 0;      
}      

请注意,由于输入是整数,我添加了一个printf

131
Number: 0x83
10000011

当然,使用循环会更容易:

int main()       
{
  int     a;
  uint8_t Mask;
  uint8_t Shift;
  scanf("%u", &a);

  printf("Number: %X\n", a);

  Mask  = 0x80;
  Shift = 7;
  
  while (Mask > 0)
  {
    printf("%d", ((a & Mask) >> Shift));
    Mask = Mask >> 1;
    Shift--;
  }

  printf("\n");
  
  return 0;      
}      
于 2020-10-27T01:43:58.037 回答