32

我有一项我认为在前台运行的服务,如何检查我的实现是否正常工作?

4

6 回答 6

36
public static boolean isServiceRunningInForeground(Context context, Class<?> serviceClass) {
      ActivityManager manager = (ActivityManager) context.getSystemService(Context.ACTIVITY_SERVICE);
      for (ActivityManager.RunningServiceInfo service : manager.getRunningServices(Integer.MAX_VALUE)) {
         if (serviceClass.getName().equals(service.service.getClassName())) {
            if (service.foreground) {
               return true;
            }

         }
      }
      return false;
   }
于 2016-03-21T09:30:45.753 回答
30
private boolean isServiceRunning(String serviceName){
    boolean serviceRunning = false;
    ActivityManager am = (ActivityManager) this.getSystemService(ACTIVITY_SERVICE);
    List<ActivityManager.RunningServiceInfo> l = am.getRunningServices(50);
    Iterator<ActivityManager.RunningServiceInfo> i = l.iterator();
    while (i.hasNext()) {
        ActivityManager.RunningServiceInfo runningServiceInfo = i
                .next();

        if(runningServiceInfo.service.getClassName().equals(serviceName)){
            serviceRunning = true;

            if(runningServiceInfo.foreground)
            {
                //service run in foreground
            }
        }
    }
    return serviceRunning;
}

如果您想知道您的服务是否在前台运行,只需打开其他一些胖应用程序,然后检查服务是否仍在运行或检查标志service.foreground

于 2011-06-23T10:27:24.017 回答
13

更有效的答案变体:https ://stackoverflow.com/a/36127260/1275265

public static boolean isServiceRunningInForeground(Context context, Class<?> serviceClass) {
   ActivityManager manager = (ActivityManager) context.getSystemService(Context.ACTIVITY_SERVICE);
   for (ActivityManager.RunningServiceInfo service : manager.getRunningServices(Integer.MAX_VALUE)) {
      if (serviceClass.getName().equals(service.service.getClassName())) {
         return service.foreground;
      }
   }
   return false;
}
于 2017-12-07T09:53:56.987 回答
5

从 API 26 开始,getRunningService()已弃用。

现在的一种解决方案是将您的活动绑定到您的服务。然后,您可以从 Activity 中调用 Service 的方法,以检查它是否正在运行。

1 - 在您的服务中,创建一个扩展 Binder 并返回您的服务的类

  public class LocalBinder extends Binder {
        MyService getService() {
            return MyService.this;
        }
    }

2 - 在您的服务中,声明活页夹

private final IBinder binder = new LocalBinder();

3 - 在您的服务中,实施onBind(),这将返回活页夹

  @Nullable
    @Override
    public IBinder onBind(Intent intent) {
        return binder;
    }

4 - 在您的服务中,创建一个检查它是否正在运行的方法(例如检查变量是否已初始化)

  public boolean isRunning() {
        // If running
            return true;
        // If not running
            return false;
        
    }

5 - 在您的活动中,创建一个包含您的服务的变量

private MyService myService;

6 - 现在,在您的活动中,您可以绑定到您的服务

private void checkIfEnabled() {
    ServiceConnection connection = new ServiceConnection() {

        @Override
        public void onServiceConnected(ComponentName className,
                                       IBinder service) {
            MyService.LocalBinder binder = (MyService.LocalBinder) service;
            myService = binder.getService();
            
            // Calling your service public method
            if(myService.isRunning()) {
                // Your service is enabled
            } else {
                // Your service is disabled
            }
        }

        @Override
        public void onServiceDisconnected(ComponentName arg0) {

        }
    };

    // Bind to MyService
    Intent intent = new Intent(this, MyService.class);
    bindService(intent, connection, Context.BIND_AUTO_CREATE);
}

有关更多信息,请查看官方文档中的绑定服务概述

于 2020-10-18T10:22:11.053 回答
1

这在Coinverse应用程序中对我有用,用于加密新闻。

这是最简洁的Kotlin解决方案。感谢此GitHub 问题中的Abbas Naqdi

@Suppress("DEPRECATION") // Deprecated for third party Services.
fun <T> Context.isServiceRunning(service: Class<T>) =
        (getSystemService(ACTIVITY_SERVICE) as ActivityManager)
            .getRunningServices(Integer.MAX_VALUE)
            .any { it.service.className == service.name }
于 2019-06-07T18:19:39.230 回答
1

很少触及亚当的回答:

@Suppress("DEPRECATION") // Deprecated for third party Services.
fun <T> Context.isServiceForegrounded(service: Class<T>) =
    (getSystemService(ACTIVITY_SERVICE) as? ActivityManager)
        ?.getRunningServices(Integer.MAX_VALUE)
        ?.find { it.service.className == service.name }
        ?.foreground == true
于 2020-09-15T14:51:54.500 回答