130

我正在使用以下方法使用 SMTP 从 Python 发送邮件。这是正确的使用方法还是我遗漏了一些陷阱？

from smtplib import SMTP
import datetime

debuglevel = 0

smtp = SMTP()
smtp.set_debuglevel(debuglevel)
smtp.connect('YOUR.MAIL.SERVER', 26)
smtp.login('USERNAME@DOMAIN', 'PASSWORD')

from_addr = "John Doe <john@doe.net>"
to_addr = "foo@bar.com"

subj = "hello"
date = datetime.datetime.now().strftime( "%d/%m/%Y %H:%M" )

message_text = "Hello\nThis is a mail from your server\n\nBye\n"

msg = "From: %s\nTo: %s\nSubject: %s\nDate: %s\n\n%s" 
        % ( from_addr, to_addr, subj, date, message_text )

smtp.sendmail(from_addr, to_addr, msg)
smtp.quit()
4

14 回答 14

123

我使用的脚本非常相似；我在这里发布它作为如何使用 email.* 模块生成 MIME 消息的示例；因此可以轻松修改此脚本以附加图片等。

我依靠我的 ISP 添加日期时间标头。

我的 ISP 要求我使用安全的 smtp 连接来发送邮件，我依赖 smtplib 模块（可在http://www1.cs.columbia.edu/~db2501/ssmtplib.py下载）

在您的脚本中，用于在 SMTP 服务器上进行身份验证的用户名和密码（下面给出虚拟值）在源代码中以纯文本形式显示。这是一个安全漏洞；但最好的选择取决于您需要（想要？）保护这些。

========================================

#! /usr/local/bin/python


SMTPserver = 'smtp.att.yahoo.com'
sender =     'me@my_email_domain.net'
destination = ['recipient@her_email_domain.com']

USERNAME = "USER_NAME_FOR_INTERNET_SERVICE_PROVIDER"
PASSWORD = "PASSWORD_INTERNET_SERVICE_PROVIDER"

# typical values for text_subtype are plain, html, xml
text_subtype = 'plain'


content="""\
Test message
"""

subject="Sent from Python"

import sys
import os
import re

from smtplib import SMTP_SSL as SMTP       # this invokes the secure SMTP protocol (port 465, uses SSL)
# from smtplib import SMTP                  # use this for standard SMTP protocol   (port 25, no encryption)

# old version
# from email.MIMEText import MIMEText
from email.mime.text import MIMEText

try:
    msg = MIMEText(content, text_subtype)
    msg['Subject']=       subject
    msg['From']   = sender # some SMTP servers will do this automatically, not all

    conn = SMTP(SMTPserver)
    conn.set_debuglevel(False)
    conn.login(USERNAME, PASSWORD)
    try:
        conn.sendmail(sender, destination, msg.as_string())
    finally:
        conn.quit()

except:
    sys.exit( "mail failed; %s" % "CUSTOM_ERROR" ) # give an error message
于 2008-09-15T17:24:40.253 回答
96

我常用的方法...没有太大区别，但有点

import smtplib
from email.MIMEMultipart import MIMEMultipart
from email.MIMEText import MIMEText

msg = MIMEMultipart()
msg['From'] = 'me@gmail.com'
msg['To'] = 'you@gmail.com'
msg['Subject'] = 'simple email in python'
message = 'here is the email'
msg.attach(MIMEText(message))

mailserver = smtplib.SMTP('smtp.gmail.com',587)
# identify ourselves to smtp gmail client
mailserver.ehlo()
# secure our email with tls encryption
mailserver.starttls()
# re-identify ourselves as an encrypted connection
mailserver.ehlo()
mailserver.login('me@gmail.com', 'mypassword')

mailserver.sendmail('me@gmail.com','you@gmail.com',msg.as_string())

mailserver.quit()

就是这样

于 2013-07-11T14:59:54.337 回答
23

此外，如果您想使用 TLS 而不是 SSL 进行 smtp auth，那么您只需更改端口（使用 587）并执行 smtp.starttls()。这对我有用：

...
smtp.connect('YOUR.MAIL.SERVER', 587)
smtp.ehlo()
smtp.starttls()
smtp.ehlo()
smtp.login('USERNAME@DOMAIN', 'PASSWORD')
...
于 2008-11-08T20:12:26.547 回答
6

我看到的主要问题是您没有处理任何错误：.login()并且.sendmail()两者都记录了它们可以抛出的异常，而且似乎.connect()必须有某种方式表明它无法连接 - 可能是底层套接字抛出的异常代码。

于 2008-09-15T16:43:36.950 回答
6

确保您没有任何防火墙阻止 SMTP。我第一次尝试发送电子邮件时，它被 Windows 防火墙和 McAfee 阻止了——我花了很长时间才找到它们。

于 2008-09-15T16:55:57.047 回答
6

那这个呢？

import smtplib

SERVER = "localhost"

FROM = "sender@example.com"
TO = ["user@example.com"] # must be a list

SUBJECT = "Hello!"

TEXT = "This message was sent with Python's smtplib."

# Prepare actual message

message = """\
From: %s
To: %s
Subject: %s

%s
""" % (FROM, ", ".join(TO), SUBJECT, TEXT)

# Send the mail

server = smtplib.SMTP(SERVER)
server.sendmail(FROM, TO, message)
server.quit()
于 2012-06-27T14:31:09.650 回答
4

以下代码对我来说工作正常：

import smtplib

to = 'mkyong2002@yahoo.com'
gmail_user = 'mkyong2002@gmail.com'
gmail_pwd = 'yourpassword'
smtpserver = smtplib.SMTP("smtp.gmail.com",587)
smtpserver.ehlo()
smtpserver.starttls()
smtpserver.ehlo() # extra characters to permit edit
smtpserver.login(gmail_user, gmail_pwd)
header = 'To:' + to + '\n' + 'From: ' + gmail_user + '\n' + 'Subject:testing \n'
print header
msg = header + '\n this is test msg from mkyong.com \n\n'
smtpserver.sendmail(gmail_user, to, msg)
print 'done!'
smtpserver.quit()

参考：http ://www.mkyong.com/python/how-do-send-email-in-python-via-smtplib/

于 2014-10-04T10:31:05.037 回答
4

我为使用 SMTP 发送邮件所做的示例代码。

import smtplib, ssl

smtp_server = "smtp.gmail.com"
port = 587  # For starttls
sender_email = "sender@email"
receiver_email = "receiver@email"
password = "<your password here>"
message = """ Subject: Hi there

This message is sent from Python."""


# Create a secure SSL context
context = ssl.create_default_context()

# Try to log in to server and send email
server = smtplib.SMTP(smtp_server,port)

try:
    server.ehlo() # Can be omitted
    server.starttls(context=context) # Secure the connection
    server.ehlo() # Can be omitted
    server.login(sender_email, password)
    server.sendmail(sender_email, receiver_email, message)
except Exception as e:
    # Print any error messages to stdout
    print(e)
finally:
    server.quit()
于 2019-04-02T10:55:20.627 回答
3

您应该确保以正确的格式格式化日期 - RFC2822。

于 2008-09-15T16:46:00.393 回答
2

看到所有这些冗长的答案了吗？请允许我通过几行来进行自我推销。

导入和连接：

import yagmail
yag = yagmail.SMTP('john@doe.net', host = 'YOUR.MAIL.SERVER', port = 26)

那么它只是一个单行：

yag.send('foo@bar.com', 'hello', 'Hello\nThis is a mail from your server\n\nBye\n')

当它超出范围时它实际上会关闭（或者可以手动关闭）。此外，它将允许您在密钥环中注册您的用户名，这样您就不必在脚本中写出您的密码（在编写之前真的让我很困扰yagmail！）

对于包/安装、提示和技巧，请查看git或pip，可用于 Python 2 和 3。

于 2015-04-18T17:27:00.127 回答
2

你可以那样做

import smtplib
from email.mime.text import MIMEText
from email.header import Header


server = smtplib.SMTP('mail.servername.com', 25)
server.ehlo()
server.starttls()

server.login('username', 'password')
from = 'me@servername.com'
to = 'mygfriend@servername.com'
body = 'That A Message For My Girl Friend For tell Him If We will go to eat Something This Nigth'
subject = 'Invite to A Diner'
msg = MIMEText(body,'plain','utf-8')
msg['Subject'] = Header(subject, 'utf-8')
msg['From'] = Header(from, 'utf-8')
msg['To'] = Header(to, 'utf-8')
message = msg.as_string()
server.sendmail(from, to, message)
于 2018-05-08T09:38:03.970 回答
2

基于这个例子，我做了以下功能：

import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText

def send_email(host, port, user, pwd, recipients, subject, body, html=None, from_=None):
    """ copied and adapted from
        https://stackoverflow.com/questions/10147455/how-to-send-an-email-with-gmail-as-provider-using-python#12424439
    returns None if all ok, but if problem then returns exception object
    """

    PORT_LIST = (25, 587, 465)

    FROM = from_ if from_ else user 
    TO = recipients if isinstance(recipients, (list, tuple)) else [recipients]
    SUBJECT = subject
    TEXT = body.encode("utf8") if isinstance(body, unicode) else body
    HTML = html.encode("utf8") if isinstance(html, unicode) else html

    if not html:
        # Prepare actual message
        message = """From: %s\nTo: %s\nSubject: %s\n\n%s
        """ % (FROM, ", ".join(TO), SUBJECT, TEXT)
    else:
                # https://stackoverflow.com/questions/882712/sending-html-email-using-python#882770
        msg = MIMEMultipart('alternative')
        msg['Subject'] = SUBJECT
        msg['From'] = FROM
        msg['To'] = ", ".join(TO)

        # Record the MIME types of both parts - text/plain and text/html.
        # utf-8 -> https://stackoverflow.com/questions/5910104/python-how-to-send-utf-8-e-mail#5910530
        part1 = MIMEText(TEXT, 'plain', "utf-8")
        part2 = MIMEText(HTML, 'html', "utf-8")

        # Attach parts into message container.
        # According to RFC 2046, the last part of a multipart message, in this case
        # the HTML message, is best and preferred.
        msg.attach(part1)
        msg.attach(part2)

        message = msg.as_string()


    try:
        if port not in PORT_LIST: 
            raise Exception("Port %s not one of %s" % (port, PORT_LIST))

        if port in (465,):
            server = smtplib.SMTP_SSL(host, port)
        else:
            server = smtplib.SMTP(host, port)

        # optional
        server.ehlo()

        if port in (587,): 
            server.starttls()

        server.login(user, pwd)
        server.sendmail(FROM, TO, message)
        server.close()
        # logger.info("SENT_EMAIL to %s: %s" % (recipients, subject))
    except Exception, ex:
        return ex

    return None

如果您仅传递body，则将发送纯文本邮件，但如果您将html参数与body参数一起传递，则将发送 html 电子邮件（对于不支持 html/mime 类型的电子邮件客户端，回退到文本内容）。

示例用法：

ex = send_email(
      host        = 'smtp.gmail.com'
   #, port        = 465 # OK
    , port        = 587  #OK
    , user        = "xxx@gmail.com"
    , pwd         = "xxx"
    , from_       = 'xxx@gmail.com'
    , recipients  = ['yyy@gmail.com']
    , subject     = "Test from python"
    , body        = "Test from python - body"
    )
if ex: 
    print("Mail sending failed: %s" % ex)
else:
    print("OK - mail sent"

顺便提一句。如果您想将 gmail 用作测试或生产 SMTP 服务器，请启用对安全性较低的应用程序的临时或永久访问权限：

于 2020-03-03T16:04:37.930 回答
2

或者

import smtplib
 
from email.message import EmailMessage
from getpass import getpass


password = getpass()

message = EmailMessage()
message.set_content('Message content here')
message['Subject'] = 'Your subject here'
message['From'] = "USERNAME@DOMAIN"
message['To'] = "you@mail.com"

try:
    smtp_server = None
    smtp_server = smtplib.SMTP("YOUR.MAIL.SERVER", 587)
    smtp_server.ehlo()
    smtp_server.starttls()
    smtp_server.ehlo()
    smtp_server.login("USERNAME@DOMAIN", password)
    smtp_server.send_message(message)
except Exception as e:
    print("Error: ", str(e))
finally:
    if smtp_server is not None:
        smtp_server.quit()

如果要使用端口 465，则必须创建一个SMTP_SSL对象。

于 2021-01-22T22:01:45.307 回答
1

这是 Python 3.x 的一个工作示例

#!/usr/bin/env python3

from email.message import EmailMessage
from getpass import getpass
from smtplib import SMTP_SSL
from sys import exit

smtp_server = 'smtp.gmail.com'
username = 'your_email_address@gmail.com'
password = getpass('Enter Gmail password: ')

sender = 'your_email_address@gmail.com'
destination = 'recipient_email_address@gmail.com'
subject = 'Sent from Python 3.x'
content = 'Hello! This was sent to you via Python 3.x!'

# Create a text/plain message
msg = EmailMessage()
msg.set_content(content)

msg['Subject'] = subject
msg['From'] = sender
msg['To'] = destination

try:
    s = SMTP_SSL(smtp_server)
    s.login(username, password)
    try:
        s.send_message(msg)
    finally:
        s.quit()

except Exception as E:
    exit('Mail failed: {}'.format(str(E)))
于 2018-08-03T22:39:23.333 回答