我希望在 my_string = '01001010' 中添加前导零,以确保至少有 'length' 位字符串,其中 length >= len(my_string)
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我已经定义了一个函数,它将未知基数的整数(十六进制、十进制、八进制、二进制等)转换为位。这些位用零填充到用户定义的最小长度,并在必要时溢出到额外的位而不填充零。
def convert_bits(obj, **kwargs):
if 'base' in kwargs:
base = int(kwargs.get('base'))
else:
base = 10
if 'location' in kwargs:
location = int(kwargs.get('location'))
else:
location = -1
if 'subroutine' in kwargs:
subroutine = str(kwargs.get('subroutine'))
else:
subroutine = ''
try:
if 'length' in kwargs:
length = int(kwargs.get('length'))
bitstream = "{0:0{1:}b}".format(int(str(obj), base), length)
if len(bitstream) != length:
raise OverflowException(
bitstream=bitstream, length=length, location=location,
subroutine=subroutine)
else:
bitstream = "{0:0b}".format(int(str(obj), base))
except Exception as e:
print(f"Exception in convert_bits method: {e}\n")
return bitstream
class OverflowException(Exception):
def __init__(self, **kwargs):
if kwargs:
try:
self.length = int(kwargs.get('length'))
self.bitstream = str(kwargs.get('bitstream'))
self.location = int(kwargs.get('location'))
self.subroutine = str(kwargs.get('subroutine'))
except:
print('exception intializing OverflowException\n')
self.length = 0
self.bitstream = ''
def __str__(self):
if self.bitstream and self.length:
if self.subroutine and self.location is not None:
return f"OVERFLOW! Bitstream has {len(self.bitstream)} bits, exceeding {self.length} at index:{self.location} in {self.subroutine}"
else:
print('No location / subroutine found!\n')
return f"OVERFLOW! Bitstream has {len(self.bitstream)} bits, exceeding {self.length}"
else:
return f"OVERFLOW!"
于 2020-10-23T17:42:21.127 回答