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我怎样才能打印球员的名字和他们的分数？

**（玩家）有（得分）点

这是我的代码

#python 3.7.1
print ("Hello, Dcoder!")

players = ["Akshit","Bhavya", "Hem", "Jayu", "Jay M", "Jay Savla", "Miraj", "Priyank", "PD", "Pratik"]
score = [0,0,0,0,0,0,0,0,0,0]
#0 = Akshit
#1 = Bhavya
#2 = Hem
#3 = Jayu
#4 = Jay M
#5 = Jay Savla
#6 = Miraj
#7 = Priyank
#8 = PD
#9 = Pratik
#10 = Shamu

print (players)
print (score)

players.append("Shamu")
score. append(0)

#RRvCSK
score[9] = (score[9]+100)
score[7] = (score[7]+50)
score[4] = (score[4]+30)

print ("Result")

print (players)
print (score)
4

3 回答 3

1 
players = ["Akshit","Bhavya", "Hem", "Jayu", "Jay M", "Jay Savla", "Miraj", "Priyank", "PD", "Pratik"]
score = [0,1,2,3,4,5,6,7,8,9]
   
for player, sc in zip(players, score):
    print("{} has {} points".format(player, sc))

输出：

Akshit has 0 points
Bhavya has 1 points
Hem has 2 points
Jayu has 3 points
Jay M has 4 points
Jay Savla has 5 points
Miraj has 6 points
Priyank has 7 points
PD has 8 points
Pratik has 9 points

zip1通过聚合来自每个可迭代对象（这里，我们有players和score列表）的元素来创建一个迭代器。players来自和的每个元素score都被放在一起，然后在下一行打印到控制台。

于 2020-10-20T06:05:07.447 回答
0

使用字典：

players = ["Akshit","Bhavya", "Hem", "Jayu", "Jay M", "Jay Savla", "Miraj", "Priyank", "PD", "Pratik"]
score = [0,0,0,0,0,0,0,0,0,0]

dct = {k: v for k, v in zip(players, score)}

dct["Akshit"] += 100
print(dct)

输出

{'Akshit': 100,
 'Bhavya': 0,
 'Hem': 0,
 'Jay M': 0,
 'Jay Savla': 0,
 'Jayu': 0,
 'Miraj': 0,
 'PD': 0,
 'Pratik': 0,
 'Priyank': 0}
于 2020-10-20T06:06:43.343 回答
0

如果我理解了这个问题，这很容易。我很确定是这样的：

#python 3.7.1
print ("Hello, Dcoder!")

players = ["Akshit","Bhavya", "Hem", "Jayu", "Jay M", "Jay Savla", "Miraj", "Priyank", "PD", "Pratik"]
score = [0,0,0,0,0,0,0,0,0,0]
#0 = Akshit
#1 = Bhavya
#2 = Hem
#3 = Jayu
#4 = Jay M
#5 = Jay Savla
#6 = Miraj
#7 = Priyank
#8 = PD
#9 = Pratik
#10 = Shamu

print(players)
print(score)

players.append("Shamu")
score.append(0)

#RRvCSK
score[9] = (score[9]+100)
score[7] = (score[7]+50)
score[4] = (score[4]+30)

print("Result is: ")

for i in range(11):
    print(f"{players[i]} has {str(score[i])} points")

我所做的只是添加一个 for 循环，每次都会打印玩家的姓名和得分。

于 2020-10-20T06:13:43.710 回答