python - 如何访问 xmlns 命名空间 webservices 中的请求响应？

Question

有一个 Web 服务返回类似这样的内容，我想在这个响应中访问id。我该怎么办？

<?xml version="1.0" encoding="utf-8"?>
<string xmlns="http://tempuri.org/">{"id":"1819","responseCode":"0","responseMessage":"0"}</string>

另外，我的功能在这里：

import requests
def sen_request():
    url = "somewhere.com/somewhere.asmx/new_one"
    payload = {}
    headers= {}
    response = requests.request("GET", url, headers=headers, data = payload)
    return (response)

• 我尝试使用response.json()访问 JSON 中的响应，但出现此错误：

Exception Type:   JSONDecodeError
Exception Value: Expecting value: line 1 column 1 (char 0)

Answer 1

该代码使用 json lib 和 XML lib 解析以提取 id

import json
import xml.etree.ElementTree as ET

data = '''<?xml version="1.0" encoding="utf-8"?>
<string xmlns="http://tempuri.org/">{"id":"1819","responseCode":"0","responseMessage":"0"}</string>'''

data1 = '''<?xml version="1.0" encoding="utf-8"?><string xmlns="tempuri.org">{"id":{"id1":"1819"},"responseCode":"0","responseMessage":"0"}</string>'''

root = ET.fromstring(data)
print(json.loads(root.text)['id'])

root = ET.fromstring(data1)
print(json.loads(root.text)['id']['id1'])

输出

1819
1819