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花一些时间尝试学习 Javascript 以成为更好的开发人员。我对这段代码有一点问题。

function howOld (age, year) {
  let theCurrentYear = 2020;
  const yearDifference = year - theCurrentYear;
  const newAge = Math.abs(age + yearDifference);
  const positiveNewAge = newAge * -1;
  
  if (newAge > age) {
    return `You will be ${newAge} in the year ${year}`;
  } else if (newAge < 0) {
    return `The year ${year} was ${positiveNewAge} years before you were born`;
  } else if (newAge > 0 && newAge < age) {
    return `You were ${positiveNewAge} in the year ${year}`;
  }
};

console.log(howOld(28,2019));

这是它应该做的：

编写一个函数 howOld()，它有两个数字参数：age 和 year，并返回当前处于该年龄的人在该年已经（或将要）的年龄。处理三种不同的情况：

如果年份是未来，则应返回以下格式的字符串：

'You will be [calculated age] in the year [year passed in]' 如果年份是他们出生之前的年份，则应返回以下格式的字符串：

'The year [year passed in] is [calculated number of years] before you'rebirth' 如果年份是过去但不在此人出生之前，则应返回以下格式的字符串：

'你是 [计算年龄] 在 [过去的年份]'

我遇到的问题是让 newAge 成为一个正数，这样我就可以将它作为一个正数传递给字符串。我已经尝试过 Math.abs() 并将 newAge 乘以 -1，但我似乎无法让它变为正数。

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1 回答 1

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感谢@vlaz 让我再试一次。这是我再次尝试后得出的答案。

function howOld (age, year) {
  let theCurrentYear = 2020;
  const yearDifference = year - theCurrentYear;
  const newAge = age + yearDifference;
  const positiveNewAge = Math.abs(newAge);
  
  if (newAge > age) {
    return `You will be ${newAge} in the year ${year}`;
  } else if (newAge < 0) {
    return `The year ${year} was ${positiveNewAge} years before you were born`;
  } else if (newAge > 0 && newAge < age) {
    return `You were ${positiveNewAge} in the year ${year}`;
  } else if (year === theCurrentYear) {
    return `You are ${age} in the year ${2020}`;
  }
};

console.log(howOld(28,1991));
于 2020-10-13T15:24:36.580 回答