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第一篇文章，我在这个问题上处于死胡同。

（一些背景）我有一个树莓派 PiZero，我正在开发一个气象站，到目前为止它记录温度、湿度和压力，并将数据发送到 windy.com API。最近我添加了一个翻斗式雨量计。这有 2 根电线连接到 GPIO，当水桶倾斜时，它会瞬间与电路竞争，基本上是按下按钮！

这里的目标是每小时计算一次提示，然后重置。在重置之前，将此数据发送到日志文件 + Windy API。这是我正在努力的部分。

我对 python 很擅长，但我正处于真正的作家障碍时刻，这是一个我从片段中拼凑起来的小程序，它计算了测试的技巧

/usr/bin/python3
import requests
from gpiozero import Button
import time

rain_sensor = Button(27)
bucket_size = 0.2794
count = 0

    def bucket_tipped():
    global count
    count = count + 1
    print(count * bucket_size)

def reset_rainfall():
    global count
    count = 0


#display and log results
def timed_loop():
reset_rainfall
timeout = time.monotonic() + 3600   # 1 hour from now
while True:
    if time.monotonic() > timeout:  # break if timeout time is reached
        rain_sensor.when_pressed = bucket_tipped
        time.sleep(1)          # Short sleep so loop can be interupted
        continue
print count


  # close the log file and exit nicely
 GPIO.cleanup()
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1 回答 1

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看起来你在循环中不断地设置你的rainto 。0while True:

编辑： 为你的循环尝试这样的事情。

def timed_loop():
    rain = 0
    timeout = time.monotonic() + 3600   # 1 hour from now
    while True:
        if time.monotonic() > timeout:  # break if timeout time is reached
            # You place your code here that you want to run every hour. 
            # After that the loop restarts
            rain = 1  
            time.sleep(1)          # Short sleep so loop can be interupted
            continue

编辑3：

使用以下代码，您可以在指定的时间内记录按钮按下。

import time

def bucket_tip_counter():
    recording_time_timeout = 3600  # Amount of seconds you want to have the timer run
    recording_time = time.monotonic() + recording_time_timeout
    button_timeout = 1  # This timeout is here so the button doesnt trigger the count more then once for each trigger
                        # You have to modify this to your needs. If the button stays activated for a few seconds you need to set the timer accordingly.
    count = 0           # Sets the counter to 0 at the start
    button = 0          # Here you need to replace the 0 with the GPIO pin that returns True if the button is pressed
    while True:         # starts the loop

        if button:         # if button gets pressed/bucket tipped
            count += 1     # up count by one
            time.sleep(button_timeout)  # wait specified timeout to make sure button isnt pressed anymore

        if time.monotonic() > recording_time:  # If the recording_time is reached the loop triggers this if condition
            print(count)   # print count
                           # Here you can also place code that you want to run when the hour is over
                           # Note that the counter wont start back up until that code is finished.

            count = 0      # set count back to 0
            recording_time = time.monotonic() + recording_time_timeout  # Set a new timer so the hour can start anew
            continue   # restart the loop

        time.sleep(1)  # small sleep to stop CPU hogging.
于 2020-10-12T11:18:41.883 回答