我在 Django 中创建了一个不同的按钮,我撞到了墙上。我正在使用 ajax 抓取 id 并发布以呈现到字符串。当第一次单击按钮时,一切都很好,但 render_to_string 不返回值 attr。我不知道为什么?
在我的观点中定义:
def like_post(request):
# post = get_object_or_404(Post, id=request.POST['post_id'])
id = request.POST.get('id')
post = get_object_or_404(Post, id=id)
# check if this user already
is_liked = False
if post.likes.filter(id=request.user.id).exists():
post.likes.remove(request.user)
is_liked = False
else:
post.likes.add(request.user)
is_liked = True
context = {
'is_liked': is_liked,
'value': id,
}
if request.is_ajax():
html = render_to_string('post/like_section.html', context, request=request)
return JsonResponse({'form': html})
正在渲染的部分:
<div id="like-section">
{% include 'post/like_section.html' %}
</div>
我的jQuery
$(document).on('click', '#like', function(e) {
e.preventDefault();
var id = $(this).attr("value");
var url = '{% url "like_post" %}';
$.ajax({
type: 'POST',
url: url,
data: {
id: id,
csrfmiddlewaretoken: '{{ csrf_token }}'
},
dataType: 'json',
success: function(response) {
$('#like-section').html(response['form'])
},
error: function(rs, e) {
console.log(rs.responseText)
}
});
});
正在渲染的部分
<form action='{% url "like_post" %}' method="post">
{% csrf_token %} {% if is_liked %}
<button name="post_id" class="likes" id="like" type="submit" value="{{ Post.id }}" like-count="{{ Post.likes.count }}">click 1</button> {% else %}
<button name="post_id" class="likes" id="like" type="submit" value="{{ Post.id }}" like-count="{{ Post.likes.count }}">click 2</button> {% endif %}
</form>
{{Post.id}} 没有通过 render_to_string 渲染我得到的结果是这样的:
<form action='/like/' method="post">
<input type="hidden" name="csrfmiddlewaretoken" value="0isfVRqNKFrDpFjCBi8jdFUgYzaw13YsEdPZV0dwi3SyExUmfOKLZUgFxaDAWhQ1">
<button name="post_id" class="likes" id="like" type="submit" value="" like-count="">click 2</button>
</form>
似乎变量没有被拾取,如果我硬编码任何数字并且没有从数据库中提取,因为{{ Post.id }}
一切似乎都工作正常。知道我缺少什么吗?
提前致谢