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我一直在尝试循环左连接（使用 R）。我需要创建一个表，其中的列代表更大表中的样本。新表的每一列都应代表这些样本中的每一个。

library(tidyr)

largetable <- data.frame(PlotCode=c(rep("Plot1",20),rep("Plot2",20)),
                         Category=c(rep("A",8),rep("B",8),rep("C",4),rep("A",12),rep("B",4),rep("C",4)))
                         
a <- data.frame(PlotCode=c("Plot1","Plot1","Plot2","Plot2"),
                Category=c("A","B","A","B"))

##example of code to loop over 100 left joins derived from samples of two elements from a large table. It fails to create the columns.
for (i in 1:100){
  count <- largetable %>% group_by(PlotCode) %>% sample_n(2, replace = TRUE)%>%
    count(PlotCode,Category)
  colnames(count)[3] <- paste0("n",i)
  b <- left_join(a, count, by = c("PlotCode","Category"))
}

##example of desired output table. Columns n1 to n100 should change depending of samples.
b <- data.frame(PlotCode=c("Plot1","Plot1","Plot2","Plot2"),
                Category=c("A","B","A","B"),
                n1=c(2,1,0,1),
                n2=c(1,1,1,1),
                n3=c(2,0,1,2))

如何循环左连接，使每一列对应一个不同的样本？

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1 回答 1

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我们可以使用/代替for循环来重复处理时间。rerunreplicaten

在每次迭代中，我们从每行中随机选择 2 行，PlotCode因此您将拥有count可以使用并根据您的选择重命名列并替换为 0 的列表。CategorynreduceNA

library(dplyr)
library(purrr)

n <- 10

rerun(n, largetable %>% 
  group_by(PlotCode) %>% 
  slice_sample(n = 2, replace = TRUE) %>%
  count(PlotCode,Category)) %>%
  reduce(full_join, by = c('PlotCode', 'Category')) %>%
  rename_with(~paste0('n', seq_along(.)), starts_with('n')) %>%
  mutate(across(starts_with('n'), tidyr::replace_na, 0))

#  PlotCode Category    n1    n2    n3    n4    n5    n6    n7    n8    n9   n10
#  <chr>    <chr>    <dbl> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl>
#1 Plot1    A            1     0     2     2     0     1     0     1     2     2
#2 Plot1    B            1     0     0     0     1     1     2     1     0     0
#3 Plot2    B            1     0     0     0     1     0     0     0     0     0
#4 Plot2    C            1     2     0     0     0     0     1     1     0     0
#5 Plot1    C            0     2     0     0     1     0     0     0     0     0
#6 Plot2    A            0     0     2     2     1     2     1     1     2     2
于 2020-10-06T07:38:45.770 回答