我有一个包含以下字段和数据的表。
RefNo Year Month Code
1 2010 7 A
2 2009 10 B
3 2010 8 A
4 2010 5 B
从这里我必须找出特定代码的最大值(年,月)。结果必须是
3 2010 8 A
1 2010 7 B
请帮我解决这个问题。
我有一个包含以下字段和数据的表。
RefNo Year Month Code
1 2010 7 A
2 2009 10 B
3 2010 8 A
4 2010 5 B
从这里我必须找出特定代码的最大值(年,月)。结果必须是
3 2010 8 A
1 2010 7 B
请帮我解决这个问题。
SELECT
*
FROM
(
SELECT
ROW_NUMBER() OVER (PARTITION BY Code ORDER BY Year DESC, Month DESC) AS row_number,
*
FROM
myTable
)
AS orderedTable
WHERE
row_number = 1
编辑现在对于在 MySQL 中工作的版本......
SELECT
*
FROM
myTable
WHERE
Year * 12 + Month = (SELECT MAX(Year * 12 + Month) FROM myTable AS lookup WHERE Code = myTable.Code)
编辑访问 SQL 后,可以确认这更快...
WHERE
Year = (SELECT MAX(Year) FROM myTable AS lookup WHERE Code = myTable.Code)
AND Month = (SELECT MAX(Month) FROM myTable AS lookup WHERE Code = myTable.Code AND Year = myTable.Year)
这对你有用吗?这个想法是将 Year 和 Month 组合成 SQL 可以获取 MAX 的东西,然后将表加入到这个修改后的版本中。
SELECT OriginalTable.RefNo, OriginalTable.Year, OriginalTable.Month, OriginalTable.Code
FROM table OriginalTable,
(SELECT Code, MAX(Year*100 + Month) AS CombinedDate
FROM table
GROUP BY Code) AS MaximumResults
WHERE OriginalTable.Code = MaximumResults.Code
AND OriginalTable.Year = MaximumResults.CombinedDate / 100
AND OriginalTable.Month = MaximumResults.CombinedDate % 100
这个想法在这里得到了更彻底的解释:http ://www.techonthenet.com/sql/max.php
说你的表名是“table1”然后
select * from
(select * from table1 where Year in (select max(Year) from table1)) abc
where Month not in (select min(Month) from abc)
我有解决方案:
Select Month(B.NewDate) Mon, Year(B.NewDate) Year, Code, PK
from T1 A ,
(Select Max(Str_To_Date(Concat('01',',',Month,',',Year), '%d,%m,%Y')) as NewDate, Code C
from T1 group by Code) B
Where PK = (Select PK from T1
where Year = Year(B.NewDate) and Month = Month(B.NewDate) and Code = A.Code)
and A.Code = C
group by Code