Laravel BACK PACK 管理面板。我想使用匿名全局范围。这是链接。我在下面的屏幕截图中有两个表（用户、帐户配置文件），您可以在帐户配置文件中看到我们有一列 user_id。
首先，让我解释一下。我确实放在用户模型中的代码。
protected static function boot(){
parent::boot();
$userId = 1;
static::addGlobalScope('users', function (Builder $builder) use ($userId) {
return $builder->where('users.id', $userId);
});
}
这给了我管理面板中的记录。（因为我只获取 user_id "1" 记录） 记录
但现在我想加入两个表（用户、帐户配置文件）之间。我知道我们将在用户模型中编写查询。
protected static function boot(){
parent::boot();
$userId = 1;
static::addGlobalScope('users', function (Builder $builder) use ($userId) {
return $builder->join("accounts_profiles_biz", 'users.id', '=', 'accounts_profiles_biz.user_id');
});
}
但我得到了那个错误。
response_message: [
{
code: 9997,
message: "SQLSTATE[42702]: Ambiguous column: 7 ERROR: column reference "id" is ambiguous LINE 1: ...s"."id" = "accounts_profiles_biz"."user_id" where "id" = $1 ... ^ (SQL: select * from "users" inner join "accounts_profiles_biz" on "users"."id" = "accounts_profiles_biz"."user_id" where "id" = 1 and "users"."deleted_at" is null limit 1), File: D:\xampp\htdocs\laravel\vendor\laravel\framework\src\Illuminate\Database\Connection.php, Line: 669",
Exception Code: "SQLSTATE[42702]: Ambiguous column: 7 ERROR: column reference "id" is ambiguous LINE 1: ...s"."id" = "accounts_profiles_biz"."user_id" where "id" = $1 ... ^ (SQL: select * from "users" inner join "accounts_profiles_biz" on "users"."id" = "accounts_profiles_biz"."user_id" where "id" = 1 and "users"."deleted_at" is null limit 1)"
}
]
太感谢了。