1

我想使用我处置的 zm_auth_token 对用户进行身份验证：

目前，我正在这样做：

    LmcAuthRequest auth = new LmcAuthRequest();
    auth.setUsername(userName);
    auth.setPassword(password);
    LmcAuthResponse authResp = (LmcAuthResponse) auth.invoke(serverURL);
    LmcSession session = authResp.getSession();

但我想使用我拥有的 zm_auth_token。这该怎么做 ？？？谢谢

4

3 回答 3

2

现在不推荐使用 zimbra Lmc 方法......如果你想使用 SOAP，他们更喜欢使用 ZMailBox （它对我不起作用），我使用了这种方法：

// Create the connection where we're going to send the file.
        URL url = new URL(SOAPUrl);
        URLConnection connection = url.openConnection();
        HttpURLConnection httpConn = (HttpURLConnection) connection;

        String  postContent = "<soap:Envelope xmlns:soap=\"http://www.w3.org/2003/05/soap-envelope\">"+
        "<soap:Header>" +
        "<context xmlns=\"urn:zimbra\">" +
        "<format type=\"js\"/>" +
        "<authToken>" + authToken + "</authToken>" +
        "</context>" +
        "</soap:Header>" +
        "<soap:Body>" + 
        "<GetFolderRequest xmlns=\"urn:zimbraMail\" />" +
        "</soap:Body>" +
        "</soap:Envelope>";

        // insert your SOAP XML!!!
        byte[] b = postContent.getBytes();

        // Set the appropriate HTTP parameters.
        httpConn.setRequestProperty( "Content-Length", String.valueOf( b.length ) );
        httpConn.setRequestProperty("Content-Type","application/soap+xml; charset=utf-8");
        httpConn.setRequestMethod( "POST" );
        httpConn.setDoOutput(true);
        httpConn.setDoInput(true);

        // Everything's set up; send the XML that was read in to b.
        OutputStream out = httpConn.getOutputStream();
        out.write( b );
        out.close();

        // Read the response and write it to standard out.
        InputStreamReader isr = new InputStreamReader(httpConn.getInputStream());
        BufferedReader in = new BufferedReader(isr);

        // read & do something with input stream...
        String s = null;
        String response = "";
        while((s=in.readLine()) != null){
            response += s;
        }
        in.close();
于 2011-06-23T09:17:52.803 回答
1 
SOAPConnectionFactory soapfactory=SOAPConnectionFactory.newInstance();
SOAPConnection soapconnection=soapfactory.createConnection();
MessageFactory messagefactory=MessageFactory.newInstance();
SOAPMessage messege=messagefactory.createMessage();
SOAPEnvelope envelop=messege.getSOAPPart().getEnvelope();
SOAPHeader header=messege.getSOAPHeader();
SOAPBody body=messege.getSOAPBody();
Name header_context=envelop.createName("context", null,"urn:zimbra");
Name auth_request=envelop.createName("AuthRequest",null,"urn:zimbraAccount");
Name account=envelop.createName("account");
Name password=envelop.createName("password");
header.addHeaderElement(header_context);
SOAPBodyElement auth_body=body.addBodyElement(auth_request);
        auth_body.addChildElement(account).addAttribute(envelop.createName("by"),"name").addTextNode("abc");//(abc==your username)
auth_body.addChildElement(password).addTextNode("1234");//(1234=your password)
URL url=new URL("http://192.168.1.67/service/soap/AuthRequest");
SOAPMessage response=soapconnection.call(messege, url);
于 2013-02-25T06:01:02.173 回答
0

您可以使用 Zimbra 库来调用 SOAP API。请检查这个答案。

于 2020-10-06T17:15:56.620 回答