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我必须从三个不同的表中查询结果，到目前为止，我已经能够单独获得单独的结果。现在我想加入这些结果。以下两段代码是我的查询。我应该以某种方式嵌套两者吗？我想从底部查询中对 s.STORE_NUM 和 str.num 进行内部连接，但是我将如何分别声明这两者？

SELECT
S.STORE_NUM,
M.YEAR_FISCAL,
--M.YEAR_445,
M.MONTH_NAME_445,
M.WEEK_START_DT_MON,
SUM(SALES_NET) - SUM(S.SALES_GCARD_NET) as SALES_WT_GC,
SUM(S.TRAFFIC_COUNT) AS TRAFFIC,
SUM(S.TICKETS_NET) AS  TRANS,
SUM(S.QTY_NET) AS UNITS,
-- Calculation level:
SUM(S.QTY_NET)/SUM(S.TRAFFIC_COUNT) AS UOT,
SUM(S.QTY_NET)/SUM(S.TICKETS_NET) AS UPT,
SUM(S.TICKETS_NET)/SUM(S.TRAFFIC_COUNT) AS CONVPCT
FROM DNA_PUBLIC..RETAIL_SALES_BY_STORE_BY_DAY S
JOIN DNA_PUBLIC.ADMIN.DAY_MAP M
ON S.DATE_DATA = M.DATE_DT
WHERE  S.DATE_DATA BETWEEN '08/24/2020' AND '09/27/2020'
AND S.SALES_NET > 0
AND S.TRAFFIC_COUNT > 0
AND S.QTY_NET > 0
AND S.TICKETS_NET > 0
AND S.STORE_NUM = 2Ah 
GROUP BY 1,2,3,4
ORDER BY S.STORE_NUM, WEEK_START_DT_MON

和

SELECT r.str_num, r.str_nam, r.str_dst, s.region_name, s.div_name, r.STR_ADDR, r.str_cty, r.str_zip5 
FROM admin.retail_store_names r JOIN admin.store_dim s ON r.str_num = s.store_num
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2 回答 2

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我想从底部查询中对 s.STORE_NUM 和 str.num 进行内部连接，但是我将如何分别声明这两者？

您可以通过将查询转换为子查询并加入外部查询来加入这两个结果集。该order by子句转到外部查询：

select t1.*, t2.*
from (
    -- first query goes here (without the "order by")
) t1
inner join (
    -- second query goes there
) t2 on t2.str_num = t1.store_num
order by t1.str_num, t2.week_start_dt_mon
于 2020-09-28T21:51:45.537 回答
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你也可以这样做 -

            SELECT
            S.STORE_NUM,
            M.YEAR_FISCAL,
            --M.YEAR_445,
            M.MONTH_NAME_445,
            M.WEEK_START_DT_MON,
            max(r.str_num) As str_num,
            max(r.str_nam) As str_nam,
            max(r.str_dst) As str_dst,
            max(st.region_name) As region_name,
            max(st.div_name) As div_name,
            max(r.STR_ADDR) As STR_ADDR,
            max(r.str_cty) As str_cty,
            max(r.str_zip5) As str_zip5,
            SUM(SALES_NET) - SUM(S.SALES_GCARD_NET) as SALES_WT_GC,
            SUM(S.TRAFFIC_COUNT) AS TRAFFIC,
            SUM(S.TICKETS_NET) AS  TRANS,
            SUM(S.QTY_NET) AS UNITS,
            -- Calculation level:
            SUM(S.QTY_NET)/SUM(S.TRAFFIC_COUNT) AS UOT,
            SUM(S.QTY_NET)/SUM(S.TICKETS_NET) AS UPT,
            SUM(S.TICKETS_NET)/SUM(S.TRAFFIC_COUNT) AS CONVPCT
            FROM DNA_PUBLIC.RETAIL_SALES_BY_STORE_BY_DAY S
            JOIN DNA_PUBLIC.ADMIN.DAY_MAP M
            ON S.DATE_DATA = M.DATE_DT
            JOIN admin.retail_store_names r
            ON S.Store_num = r.Str_num
            JOIN admin.store_dim st
            ON r.str_num = s.store_num
            WHERE  S.DATE_DATA BETWEEN '08/24/2020' AND '09/27/2020'
            AND S.SALES_NET > 0
            AND S.TRAFFIC_COUNT > 0
            AND S.QTY_NET > 0
            AND S.TICKETS_NET > 0
            AND S.STORE_NUM = 2Ah 
            GROUP BY 1,2,3,4
            ORDER BY S.STORE_NUM, M.WEEK_START_DT_MON
于 2020-09-28T22:02:11.230 回答