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我在这个问题上遵循了很多例子,但我似乎无法让它发挥作用。我可以成功地单独查询数据库,但不能在同一个查询中查询两个数据库。

我尝试了别名,指的是查询中的服务器......在名称周围放置 `` 等。没有任何效果。

所以这是我的代码

连接字符串:

/// LOCAL DATABASE
$databaseprefix = "w-";
$mysqlHost = 'localhost';
$mysqlUser = 'web123-USER1';
$mysqlPass = 'SOMEPASSWORD';
$mysqlDB = $databaseprefix . 'DATABASE1';
$conn = mysql_connect($mysqlHost,$mysqlUser,$mysqlPass,true) or die('Could not connect to SQL Server on '.$mysqlHost.' '. mysql_error());

///select remote database to work with
$localDB = mysql_select_db($mysqlDB, $conn)  or die("x1 Couldn't open database $mysqlDB");

///////////// GET THE DATABASE WE WANT TO EDIT
$remoteHost = $_SESSION['localfolder'];
$remoteUser = $_SESSION['databaseuser'];
$remotePass = $_SESSION['databasepassword'];
$remoteDB = $_SESSION['database'];
$remoteconn = mysql_connect($remoteHost,$remoteUser,$remotePass,true) or die('Could not connect to SQL Server on '.$remoteHost.' '. mysql_error());

$clientDB = mysql_select_db($remoteDB, $remoteconn)  or die("x2 Couldn't open database $remoteDB");

好的,那我有这个

$query_string = "select 
`$remoteHost`.`$remoteDB`.`pages`.`page_title`, 
`$mysqlHost`.`$mysqlDB`.`c_users`.`name`
from `$remoteHost`.`$remoteDB`.`pages`
left join `$mysqlHost`.`$mysqlDB`.`c_users`
on `$remoteHost`.`$remoteDB`.`pages`.`created_by` = `$mysqlHost`.`$mysqlDB`.`c_users`.`user_id`";

echo $query_string;
//// Query the DB's
$query = mysql_query($query_string);

echo mysql_num_rows($query);

while($row = mysql_fetch_assoc($query)) {
    echo $row['name'] . ' | ' . $row['page_title'];
}

查询的输出是这样的

select `remoteaddress.co.uk`.`remote-DB`.`pages`.`page_title`, 
`localhost`.`w-DATABASE1`.`c_users`.`name` 
from `remoteaddress.co.uk`.`remote-DB`.`pages` 
left join `localhost`.`w-DATABASE1`.`c_users` on 
`remoteaddress.co.uk`.`remote-DB`.`pages`.`created_by` = `localhost`.`w-DATABASE1`.`c_users`.`user_id`

两个连接字段都是连接上的 INT 数据类型和相同的排序规则。我不确定为什么这会失败。任何帮助,将不胜感激。

4

1 回答 1

1

那是因为您的本地连接无法直接连接到远程主机...

您可以使用 2 个查询,每个服务器一个查询

$query = mysql_query($query_string, $conn);
$query = mysql_query($query_string, $remoteconn);
于 2011-06-20T11:48:11.937 回答