我需要将此网站设置为 A(将输入保存到数据集)和 B(将即时输入显示到同一页面。我已经全部设置好了,但是每次单击提交时,我的页面都会显示我的 .php 文件。如何我要解决这个问题吗?
<!DOCTYPE html>
<html>
<head lang="en">
<meta charset="utf-8" />
<title>Newsletter Signup</title>
<link rel="stylesheet" type="text/css" href="style.css" />
<script language="javascript">
function display() {
var name = document.getElementById("name").value;
var email = document.getElementById("email").value;
var result = name + '! We will start sending our newsletter to ' + email;
document.getElementById('spanResult').textContent = result;
}
</script>
</head>
<body>
<div id="body">
<form id="Signup" action="membersList.php" method='post'>
<h2>Sign-Up</h2>
<br />
Name: <input type="text" name="name" id="name">
<br />
E-mail: <input type="text" name="email" id="email">
<br />
<input type="submit" name="submit" onclick="display()" value="submit"/>
</form>
<br />
<h3>Welcome </h3> <span id='spanResult'></span>
</div>
</body>
</html>
我的 php 文件
<?php
if(isset($_POST['submit']))
{
$xml = new SimpleXMLElement("<?xml version=\"1.0\" encoding=\"utf-8\" ?><member></member>");
$xml->addChild('name', $_POST['name']);
$xml->addChild('email', $_POST['email']);
$asXML = $xml->asXML();
$file = fopen("data.xml","w+");
fwrite($file,$asXML);
fclose($file);
print_r(error_get_last());
if(file_exists('./data.xml'))
{
$myXML = file_get_contents('./data.xml');
$xml = new SimpleXMLElement($myXML);
$xmlpretty = $xml->asXML();
// pretty print the XML in browser
header('content-type: text/xml');
echo $xmlpretty;
}
}
?>
任何改进代码的建议也将不胜感激。