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我想从 data.errors 中获取我发送的错误。我使用“https://github.com/zino-app/graphql-flutter/tree/master/packages/graphql”来获得我的回复。我的回复如下所示：

{data: {…}, status: 401, statusText: "OK", headers: {…}, config: {…}, …}
config: {url: "http://localhost:3000/graphql", method: "post", data: "{"query":"\n        query getSomeData($date: Str…variables":{"date":"2020-09-18","city":"London"}}", headers: {…}, transformRequest: Array(1), …}
data:
data: {getSomeData: null}
errors: [{…}]
__proto__: Object
headers: {content-length: "88", content-type: "application/json; charset=utf-8"}
original_status: 200
request: XMLHttpRequest {readyState: 4, timeout: 0, withCredentials: false, upload: XMLHttpRequestUpload, onreadystatechange: ƒ, …}
status: 401
statusText: "OK"
__proto__: Object

我获取数据的代码如下所示：

import 'dart:async';

import 'package:graphql/client.dart';
import 'package:flutter/material.dart';
import 'package:flutter_dotenv/flutter_dotenv.dart';

import '../shared/secure_storage.dart' as storage;

final HttpLink _httpLink = HttpLink(
  uri: DotEnv().env['BACKEND_CONNECTION'],
);

final AuthLink _authLink = AuthLink(
  getToken: () async => 'Bearer ' + storage.getToken(),
);

final Link _link = _authLink.concat(_httpLink);

final GraphQLClient _client = GraphQLClient(
  cache: InMemoryCache(),
  link: _link,
);

final String query = ''' typical query''';

class PublicConcertsBloc extends ChangeNotifier {
  //Data
  List _result;
  List get result => _result;

  //Getters

  QueryOptions get options => QueryOptions(
      documentNode: gql(query), variables: {'var1': var, 'var2': 'var2'});

  set result(List val) {
    _result = val;
    notifyListeners();
  }

  Future loadConcerts() async {
    final QueryResult result = await _client.query(options);

    if (result.data == null) {
      print("data == null");
    } else if (result.data["getSomeData"] == null) {
      print("getSomeData == getSomeData");
    } else if (result.loading) {
      print(result.loading.toString());
    } else if (result.hasException) {
      print(result.exception.toString());
    } else {
      print(result.data['getSomeData']);
      _result = result.data['getSomeData'] as List;
    }
  }
}

有人可以在这里帮助我吗？result.exception 不会向我显示想要的错误。

4

0 回答 0