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我有一段代码通过集成测试触发我的 pry 会话，但不存在单元测试。因此，我不确定哪个测试正在执行此代码，并且每次我希望它触发时都需要运行所有测试。有没有办法在撬动会话中冒泡测试/测试文件？我不需要_file_触发撬动会话的那个。

我最好的解决方案是在 pry 会话中引发错误，然后继续测试套件，希望这会弄错测试并能够在测试报告中找到该测试。这种方法有点像在黑暗中刺伤。

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1 回答 1

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您应该能够通过简单地调用来获得完整的调用堆栈caller：

$ pry
[1] pry(main)> caller
=> ["/home/john/.gem/ruby/2.7.0/gems/pry-0.13.1/lib/pry/pry_instance.rb:290:in `eval'",
 "/home/john/.gem/ruby/2.7.0/gems/pry-0.13.1/lib/pry/pry_instance.rb:290:in `evaluate_ruby'",
 "/home/john/.gem/ruby/2.7.0/gems/pry-0.13.1/lib/pry/pry_instance.rb:659:in `handle_line'",
 "/home/john/.gem/ruby/2.7.0/gems/pry-0.13.1/lib/pry/pry_instance.rb:261:in `block (2 levels) in eval'",
 "/home/john/.gem/ruby/2.7.0/gems/pry-0.13.1/lib/pry/pry_instance.rb:260:in `catch'",
 "/home/john/.gem/ruby/2.7.0/gems/pry-0.13.1/lib/pry/pry_instance.rb:260:in `block in eval'",
 "/home/john/.gem/ruby/2.7.0/gems/pry-0.13.1/lib/pry/pry_instance.rb:259:in `catch'",
 "/home/john/.gem/ruby/2.7.0/gems/pry-0.13.1/lib/pry/pry_instance.rb:259:in `eval'",
 "/home/john/.gem/ruby/2.7.0/gems/pry-0.13.1/lib/pry/repl.rb:77:in `block in repl'",
 "/home/john/.gem/ruby/2.7.0/gems/pry-0.13.1/lib/pry/repl.rb:67:in `loop'",
 "/home/john/.gem/ruby/2.7.0/gems/pry-0.13.1/lib/pry/repl.rb:67:in `repl'",
 "/home/john/.gem/ruby/2.7.0/gems/pry-0.13.1/lib/pry/repl.rb:38:in `block in start'",
 "/home/john/.gem/ruby/2.7.0/gems/pry-0.13.1/lib/pry/input_lock.rb:61:in `__with_ownership'",
 "/home/john/.gem/ruby/2.7.0/gems/pry-0.13.1/lib/pry/input_lock.rb:78:in `with_ownership'",
 "/home/john/.gem/ruby/2.7.0/gems/pry-0.13.1/lib/pry/repl.rb:38:in `start'",
 "/home/john/.gem/ruby/2.7.0/gems/pry-0.13.1/lib/pry/repl.rb:15:in `start'",
 "/home/john/.gem/ruby/2.7.0/gems/pry-0.13.1/lib/pry/pry_class.rb:191:in `start'",
 "/home/john/.gem/ruby/2.7.0/gems/pry-0.13.1/lib/pry/cli.rb:119:in `start'",
 "/home/john/.gem/ruby/2.7.0/gems/pry-0.13.1/bin/pry:13:in `<top (required)>'",
 "/home/john/.gem/ruby/2.7.0/bin/pry:23:in `load'",
 "/home/john/.gem/ruby/2.7.0/bin/pry:23:in `<main>'"]
于 2020-09-17T18:59:43.140 回答