我正在尝试在 Akka Actor 中执行以下 Scala 代码。
class FilteringService(implicit timeout: Timeout) extends Actor {
def receive: PartialFunction[Any, Unit] = {
case GetProfiles ⇒
val requester = sender
def getProfiles = {
var result = new Array[Profile](0)
println("[GET-PROFILES] Entered, making request")
val req = Get("http://localhost:9090/profiles")
implicit val profileFormat = jsonFormat16(Profile)
val responseFuture: Future[HttpResponse] = Http().singleRequest(req)
println("[GET-PROFILES] Entered, request sent")
responseFuture.onComplete {
case Success(response) =>
println("[RES - SUCCESS] Request returned with " + response.status)
val responseAsProfiles = Unmarshal(response.entity).to[Array[Profile]]
responseAsProfiles.onComplete {
println("[UNMARSH - SUCCESS] Unmarshaling Done!")
_.get match {
case profiles: Array[Profile] =>
println("[UNMARSH - SUCCESS] Sending Profiles message to " + sender())
requester ! profiles
println("[UNMARSH - SUCCESS] Message sent to " + sender())
case _ => println("error")
}
}
case Failure(_) =>
sys.error("something wrong")
//return Future[Array[Profile]]
}
}
println("[RECEIVE] Message GetProfiles received from " + sender().toString())
getProfiles
println("[RECEIVE] Message GetProfiles invoked")
}
当 Actor 收到消息“GetProfiles”时:
1-它向远程服务器发送请求,因此操作结果是 Future[HttpResponse]
2- 如果成功,它会检索响应(一个 JSON 数组)并要求将对象解组为 Array[Profile]。(Profile 模型并不重要)。Unmarshall 方法的结果是 Future[Array[Profile]]
3-如果成功,我想将结果发送回原始发件人!
我设法做到了,但这是一个技巧,因为我将发件人保存在一个变量中,该变量在范围(请求者)中可见。我知道有管道模式,所以理论上我可以将responseAsProfiles对象发送回发送者,但是该对象是在responseFuture对象的 onComplete 方法中创建的(当然,我们必须等待它!)
就是这样!在这种情况下,如何使用管道模式将结果发送回发送者?提前致谢!!!