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我有两个数组 partyCtx 和 planList

partyCtx 看起来像这样:

partyCtx: Array(5)
0: {planCode: "PLN00062", planShortName: "Federal Home Loan Bank of A", employerPartyID: "", employerShortName: "", hasPayrollCenter: false, …}
1: {planCode: "PLN00125", planShortName: "Federal Home Loan Bank of B", employerPartyID: "", employerShortName: "", hasPayrollCenter: false, …}
2: {planCode: "PLN01633", planShortName: "Federal Home Loan Bank of C", employerPartyID: "", employerShortName: "", hasPayrollCenter: false, …}
3: {planCode: "PLN01819", planShortName: "Federal Home Loan Bank of D", employerPartyID: "", employerShortName: "", hasPayrollCenter: false, …}
4: {planCode: "PLN06806", planShortName: "Federal Home Loan Bank of E", employerPartyID: "", employerShortName: "", hasPayrollCenter: true, …}
length: 5

计划列表看起来像这样

planList: Array(2)
0: "PLN06806"
1: "PLN00125"
length: 2

现在我需要一个数组,你可以在其中选择计划列表并从 partyctx 过滤/映射它,所以它应该看起来像

result: Array(2)
0: {planCode: "PLN06806", planShortName: "Federal Home Loan Bank of E"}
1: {planCode: "PLN00125", planShortName: "Federal Home Loan Bank of B"}
length: 2

我如何获得结果数组?

4

1 回答 1

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只需过滤和映射它:

const result = partyCtx.filter(p => planList.includes(p.planCode)) // filter on items with planCode in planList
        .map(({planCode, planShortName})  => ({planCode, planShortName})) // map to planCode and planShortName
于 2020-09-15T16:40:17.783 回答