8

我想通过函数处理查询中的一行，我将行作为结构传递。

理想...

<cfloop query="myquery">
 #myfunction(#row#)#
</cfloop>

我也可以这样设置...

<cfloop query="myquery">
 #myfunction(#col1#,#col2#,#col3#,#col4#)#
</cfloop>

但我不想。我一直无法找到提取行的简单方法，但我想我会问。

4

5 回答 5

14

为单行找到了一个看起来更优雅的解决方案

<cfscript>
    function GetQueryRow(query, rowNumber) {
        var i = 0;
        var rowData = StructNew();
        var cols    = ListToArray(query.columnList);
        for (i = 1; i lte ArrayLen(cols); i = i + 1) {
            rowData[cols[i]] = query[cols[i]][rowNumber];
        }
        return rowData;
    }
</cfscript>
于 2011-06-24T01:51:37.433 回答
11

Adobe ColdFusion 11 引入QueryGetRow了将行从查询转换为结构。

于 2017-08-15T21:25:53.680 回答
3

This is the Class from Ben's site without the comments

<--- --------------------------------------------------------------------------------------- ----

    Blog Entry:
    Ask Ben: Converting A Query To A Struct

    Author:
    Ben Nadel / Kinky Solutions

    Link:
    http://www.bennadel.com/index.cfm?event=blog.view&id=149

    Date Posted:
    Jul 19, 2006 at 7:32 AM

---- --------------------------------------------------------------------------------------- --->


<cffunction name="QueryToStruct" access="public" returntype="any" output="false"
    hint="Converts an entire query or the given record to a struct. This might return a structure (single record) or an array of structures.">
    <cfargument name="Query" type="query" required="true" />
    <cfargument name="Row" type="numeric" required="false" default="0" />

    <cfscript>
        var LOCAL = StructNew();
        if (ARGUMENTS.Row){
            LOCAL.FromIndex = ARGUMENTS.Row;
            LOCAL.ToIndex = ARGUMENTS.Row;
        } else {
            LOCAL.FromIndex = 1;
            LOCAL.ToIndex = ARGUMENTS.Query.RecordCount;
        }
        LOCAL.Columns = ListToArray( ARGUMENTS.Query.ColumnList );
        LOCAL.ColumnCount = ArrayLen( LOCAL.Columns );
        LOCAL.DataArray = ArrayNew( 1 );
        for (LOCAL.RowIndex = LOCAL.FromIndex ; LOCAL.RowIndex LTE LOCAL.ToIndex ; LOCAL.RowIndex = (LOCAL.RowIndex + 1)){
            ArrayAppend( LOCAL.DataArray, StructNew() );
            LOCAL.DataArrayIndex = ArrayLen( LOCAL.DataArray );
            for (LOCAL.ColumnIndex = 1 ; LOCAL.ColumnIndex LTE LOCAL.ColumnCount ; LOCAL.ColumnIndex = (LOCAL.ColumnIndex + 1)){
                LOCAL.ColumnName = LOCAL.Columns[ LOCAL.ColumnIndex ];
                LOCAL.DataArray[ LOCAL.DataArrayIndex ][ LOCAL.ColumnName ] = ARGUMENTS.Query[ LOCAL.ColumnName ][ LOCAL.RowIndex ];
            }
        }
        if (ARGUMENTS.Row){
            return( LOCAL.DataArray[ 1 ] );
        } else {
            return( LOCAL.DataArray );
        }
    </cfscript>
</cffunction>

usage...

<!--- Convert the entire query to an array of structures. --->
<cfset arrGirls = QueryToStruct( qGirls ) />

<!--- Convert the second record to a structure. --->
<cfset objGirl = QueryToStruct( qGirls, 2 ) />
于 2011-06-18T17:33:06.243 回答
3

Ben Nadel 发布了一篇关于此的博客文章，其中他提供了一个示例 UDF，它将查询转换为结构，它接受一个可选的行参数，允许您将该查询中的单行转换为结构。看看这里。

于 2011-06-17T17:41:42.153 回答
0

另一种解决方案是：

function QueryToStruct(query){
    var cols    = ListToArray(query.columnList);
    var salida  = query.map(function(v=0,i,a){
                       return {'#cols[1]#':v};
                  });  
    return ValueArray(salida,'#cols[1]#');
}
于 2017-11-14T22:09:52.170 回答