1

我通过 VideoJS 录制视频。代码如下所示：

// Video recording via webcam
var videoMaxLengthInSeconds = 180;

// Inialize the video player
let videoBlob;
var player = videojs("myVideo", {
    controls: true,
    width: 720,
    height: 480,
    fluid: false,
    plugins: {
        record: {
            audio: true,
            video: true,
            maxLength: videoMaxLengthInSeconds,
            debug: true,
            videoMimeType: "video/mp4"
        }
    }
}, function() {
    // print version information at startup
    videojs.log(
        'Using video.js', videojs.VERSION,
        'with videojs-record', videojs.getPluginVersion('record'),
        'and recordrtc', RecordRTC.version
    );
});

// error handling for getUserMedia
player.on('deviceError', function() {
    console.log('device error:', player.deviceErrorCode);
});

// Handle error events of the video player
player.on('error', function(error) {
    console.log('error:', error);
});

// user clicked the record button and started recording !
player.on('startRecord', function() {
    console.log('started recording! Do whatever you need to');
});

// user completed recording and stream is available
// Upload the Blob to your server or download it locally !
let recording;
let recordingData;
player.on('finishRecord', function() {
    // the blob object contains the recorded data that
    // can be downloaded by the user, stored on server etc.
    recordingData = player.recordedData;
    videoBlob = player.recordedData.video;
    //let myblob = new Blob(player.recordedData, { type: "video/webm" });
    let objectURL = window.URL.createObjectURL(player.recordedData)
    let downloadButton = document.getElementById('downloadButton');
    downloadButton.href = objectURL;
    downloadButton.download = "Vlog.webm";
    //recording = new File(myBlob, 'vlog.webm')
    console.log(recording)
    console.log('finished recording: ', videoBlob);
});

// Sending recorder video to server
$('#postButton').click(function() {
    // Get form data
    form = document.querySelectorAll('#form');
    let formData = new FormData(form[0]);

    let disabled = document.getElementById("commentsDisable").checked
    console.log("Comments Enabled: " + disabled)
    formData.append('commentsDisabled', disabled);

    let selection = document.getElementById('categorySelect');
    let selected = selection.options[selection.selectedIndex].value;

    // Append selected category
    formData.append('category', selected)

    //Apend YouTube embed link
    if (ytUrl) {
        formData.append('ytlink', ytUrl)
    }

    // Append recordedBlob to form data as file
    if (recordingData) {
        console.log('Recording detected: ' + recordingData)
        formData.append('videoFile', recordingData, recordingData.name);
    }

    //Append video from local upload
    if (tempFile) {
        formData.append('videoFile', tempFile);
    }

    // Send POST request via AJAX to server
    $.ajax({
        type: "POST",
        url: "/make_vlog/",
        processData: false,
        contentType: false,
        data: formData,
        success: function(response) {
            alert(response);
            //location.href = "/vlogs";
        }
    });
});``

在服务器端，我有一个 django 应用程序，它将文件存储为 .mp4 创建一个新的 Vlog 模型。

当我打开页面时，视频已加载并且可以由所有浏览器播放。除了 Safari 和 iOS 设备不播放视频（不支持格式）。

当我从文件上传视频而不是网络摄像头录制时。并且该文件是一个有效的 mp4 视频（例如从这里：example_video）该文件在每个设备和浏览器上播放。

我认为问题在于我的 js 代码中的视频编码。.webm 文件也会出现同样的问题。当我下载 webm 时，在 VLC 中转换为 mp4 并上传到服务器上，视频可以正确播放。

有没有人遇到过这样的问题？谢谢

4

1 回答 1

1

您需要将 webm 视频转换为 mp4 服务器站点以在 Safari 中播放。

在基于网络的网络摄像头录制中，每个浏览器都以特定的本机格式（mime 类型）保存。Safari 保存 mp4/mp3 而其他浏览器通常保存 webm。更改文件扩展名没有帮助。您需要转换视频。

您可以使用服务器端的 ffmpeg 将 webm 转换为 mp4。

于 2020-09-28T12:33:36.333 回答