python - 如何在另一个按钮调用的函数中检测 gpiozero 按钮按下？

Question

我需要从按钮按下触发继电器并等待信号然后释放继电器。在下面的示例代码中，该信号是 b2。我是 Python 和 Pi 的新手，但玩得很开心！:)

import RPi.GPIO as GPIO
GPIO.setmode(GPIO.BCM)
from gpiozero import Button
from signal import pause
import time

def first_button():
    print("First Pressed")
    while True: #do stuff...
        time.sleep(1)
        print("waiting...")

def second_button():
    print("Second Pressed")

b1 = Button(23)
b1.when_pressed = first_button
b2 = Button(24)
b2.when_pressed = second_button

pause()

如何在 Button 调用的现有函数仍在运行时检测按钮按下？

Answer 1

在此解决方案中，您只需打开和关闭输出

from gpiozero import Button
from signal import pause
import time

pin = #Set a pin
r = LED(pin)
b1 = Button(23)
b1.when_pressed = r.on
b2 = Button(24)
b2.when_pressed = r.off

pause()

---

这里有一个线程开始做一些事情：

from gpiozero import Button
from signal import pause
import time
import _thread

run = False
def do_stuff():
    while run: #do stuff...
        time.sleep(1)
        print("waiting...")

def first_button():
    global run
    print("First Pressed")
    run = True
    _thread.start_new_thread(do_stuff)
    

def second_button():
    global run
    print("Second Pressed")
    run = False

b1 = Button(23)
b1.when_pressed = first_button
b2 = Button(24)
b2.when_pressed = second_button

pause()