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我正在创建一个节点集群,我想在每次连接节点时都收到通知,这怎么可能?

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1 回答 1

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在方法中创建gen_server并调用。现在,每当节点加入或离开集群时,都会收到消息。net_kernel:monitor_nodes(true)initgen_server{node_up, Node}{node_down, Node}

-module(node_monitor).

-behaviour(gen_server).

%% export API
-export([start_link/0,
     stop/0
    ]).

%% export gen_server callbacks
-export([init/1,
     handle_call/3,
     handle_cast/2,
     handle_info/2,
     terminate/2,
     code_change/3]).

-record(state, {}).

-define(SERVER_NAME, ?MODULE).
%%====================================
%% API
%%====================================
start_link() ->
    gen_server:start_link({local, ?SERVER_NAME}, ?MODULE, [], []).

stop() ->
    gen_server:cast(?SERVER_NAME, stop).

%%====================================
%% callbacks
%%====================================
init([]) ->
    net_kernel:monitor_nodes(true),
    {ok, #state{}}.

terminate(_Reason, _State) ->
    ok.

code_change(_OldVsn, State, _Extra) ->
    {ok, State}.

handle_info({nodeup, _Node} = Event, State) ->
%%TODO: do something here
    {noreply, State};

handle_info({nodedown, _Node} = Event, State) ->
  %%TODO: do something here
    {noreply, State};

handle_info(_Msg, State) ->
    {noreply, State}.


handle_cast(stop, State) ->
    {stop, normal, State};
handle_cast(_Msg, State) ->
    {noreply, State}.

handle_call(_Msg, _From, State) ->
    Reply = ok,
    {reply, Reply, State}.

不过请注意,所有节点都会收到这些通知。因此,如果每个集群只有一个节点需要处理node_upnode_down通知,则需要在此 gen_server 之上实现该逻辑。

于 2020-09-02T20:47:45.170 回答