python - 使用 split() 遍历字符串中的单词

Question

我正在尝试使用循环将地址x与地址匹配并遍历字符串中的单词，一次删除一个，直到找到匹配项。我正在展示一个ywhilesplit()type error

我想知道是否有人可以帮助我正确地使用这个过程来循环单词？

x = 'Shop  9 Corner Cramer and Mary Street, Preston'
y = 'Corner Cramer and Mary Street, Preston'

def cut2(address):
    while address != y:
        p = address.split((" ",0)[0])
        p = p + 1
        
        print(f"Address Check {address}")
              
    else:
        print(address)

我想要的输出是： Corner Cramer and Mary Street, Preston

我得到的输出是：

---------------------------------------------------------------------------
TypeError                                 Traceback (most recent call last)
<ipython-input-4-a8e028e05091> in <module>
----> 1 cut2(x)

<ipython-input-3-342a77a7d0bd> in cut2(address)
      5     while address != y:
      6         p = address.split((" ",0)[0])
----> 7         p = p + 1
      8 
      9         print(f"Address Check {address}")

TypeError: can only concatenate list (not "int") to list

Answer 1

如果你print(p)在

x = 'Shop  9 Corner Cramer and Mary Street, Preston'
p = x.split((" ",0)[0])
print(p)

然后你会看到

['']

这么晚了你试着做

p = [''] + 1

这给了你错误

---

它应该是类似的东西

def cut2(address, match):
    count = 0
    # firt check if `address` is not empty  
    while address and address != match:
        parts = address.split(" ", 1)
        word = parts[0]
        if len(parts) > 1:
            address = parts[1]
        else:
            address = ''
        count += 1
        print(f"Address Check: {address}")
        
    if address:        
        print(f'Found after {count} step(s) | {address}')
    else:
        print('Not found')

# --- main ---

y = 'Corner Cramer and Mary Street, Preston'

x = 'Shop  9 Corner Cramer and Mary Street, Preston'
cut2(x, y)

x = 'Hello World'
cut2(x, y)

x = ''
cut2(x, y)