问题如下,如果我们打印曲线的控制点,我们会看到以下内容:
print(shape.points)
回报:
[[ 0.00000000e+00 0.00000000e+00 0.00000000e+00]
[ 0.00000000e+00 0.00000000e+00 0.00000000e+00]
[ 0.00000000e+00 0.00000000e+00 0.00000000e+00]
[ 0.00000000e+00 0.00000000e+00 0.00000000e+00]
[ 0.00000000e+00 0.00000000e+00 0.00000000e+00]
[ 0.00000000e+00 0.00000000e+00 0.00000000e+00]
[ 0.00000000e+00 0.00000000e+00 0.00000000e+00]
[ 0.00000000e+00 0.00000000e+00 0.00000000e+00]
[ 0.00000000e+00 0.00000000e+00 0.00000000e+00]
[ 0.00000000e+00 0.00000000e+00 0.00000000e+00]
[ 0.00000000e+00 0.00000000e+00 0.00000000e+00]
[ 0.00000000e+00 0.00000000e+00 0.00000000e+00]
[ 0.00000000e+00 0.00000000e+00 0.00000000e+00]
[ 0.00000000e+00 0.00000000e+00 0.00000000e+00]
[ 0.00000000e+00 0.00000000e+00 0.00000000e+00]
[ 0.00000000e+00 0.00000000e+00 0.00000000e+00]
[ 0.00000000e+00 0.00000000e+00 0.00000000e+00]
[ 0.00000000e+00 0.00000000e+00 0.00000000e+00]
[ 0.00000000e+00 0.00000000e+00 0.00000000e+00]
[ 0.00000000e+00 0.00000000e+00 0.00000000e+00]
[ 0.00000000e+00 0.00000000e+00 0.00000000e+00]
[ 0.00000000e+00 0.00000000e+00 0.00000000e+00]
[ 0.00000000e+00 0.00000000e+00 0.00000000e+00]
[ 0.00000000e+00 0.00000000e+00 0.00000000e+00]
[ 0.00000000e+00 0.00000000e+00 0.00000000e+00]
[ 0.00000000e+00 0.00000000e+00 0.00000000e+00]
[ 0.00000000e+00 0.00000000e+00 0.00000000e+00]
[ 0.00000000e+00 0.00000000e+00 0.00000000e+00]
[ 0.00000000e+00 0.00000000e+00 0.00000000e+00]
[ 0.00000000e+00 0.00000000e+00 0.00000000e+00]
[ 0.00000000e+00 0.00000000e+00 0.00000000e+00]
[ 0.00000000e+00 0.00000000e+00 0.00000000e+00]
[ 0.00000000e+00 0.00000000e+00 0.00000000e+00]
[ 3.33333333e-01 -8.16431199e-17 0.00000000e+00]
[ 6.66666667e-01 -1.63286240e-16 0.00000000e+00]
[ 1.00000000e+00 -2.44929360e-16 0.00000000e+00]
[ 1.00000000e+00 -2.44929360e-16 0.00000000e+00]
[ 1.00000000e+00 -2.61799388e-01 0.00000000e+00]
[ 8.92226904e-01 -5.21986659e-01 0.00000000e+00]
[ 7.07106781e-01 -7.07106781e-01 0.00000000e+00]
[ 7.07106781e-01 -7.07106781e-01 0.00000000e+00]
[ 5.21986659e-01 -8.92226904e-01 0.00000000e+00]
[ 2.61799388e-01 -1.00000000e+00 0.00000000e+00]
[-1.83697020e-16 -1.00000000e+00 0.00000000e+00]
[-1.83697020e-16 -1.00000000e+00 0.00000000e+00]
[-2.61799388e-01 -1.00000000e+00 0.00000000e+00]
[-5.21986659e-01 -8.92226904e-01 0.00000000e+00]
[-7.07106781e-01 -7.07106781e-01 0.00000000e+00]
[-7.07106781e-01 -7.07106781e-01 0.00000000e+00]
[-8.92226904e-01 -5.21986659e-01 0.00000000e+00]
[-1.00000000e+00 -2.61799388e-01 0.00000000e+00]
[-1.00000000e+00 1.22464680e-16 0.00000000e+00]
[-1.00000000e+00 1.22464680e-16 0.00000000e+00]
[-1.00000000e+00 2.61799388e-01 0.00000000e+00]
[-8.92226904e-01 5.21986659e-01 0.00000000e+00]
[-7.07106781e-01 7.07106781e-01 0.00000000e+00]
[-7.07106781e-01 7.07106781e-01 0.00000000e+00]
[-5.21986659e-01 8.92226904e-01 0.00000000e+00]
[-2.61799388e-01 1.00000000e+00 0.00000000e+00]
[ 6.12323400e-17 1.00000000e+00 0.00000000e+00]
[ 6.12323400e-17 1.00000000e+00 0.00000000e+00]
[ 2.61799388e-01 1.00000000e+00 0.00000000e+00]
[ 5.21986659e-01 8.92226904e-01 0.00000000e+00]
[ 7.07106781e-01 7.07106781e-01 0.00000000e+00]
[ 7.07106781e-01 7.07106781e-01 0.00000000e+00]
[ 8.92226904e-01 5.21986659e-01 0.00000000e+00]
[ 1.00000000e+00 2.61799388e-01 0.00000000e+00]
[ 1.00000000e+00 0.00000000e+00 0.00000000e+00]
[ 1.00000000e+00 0.00000000e+00 0.00000000e+00]
[ 6.66666667e-01 0.00000000e+00 0.00000000e+00]
[ 3.33333333e-01 0.00000000e+00 0.00000000e+00]
[ 0.00000000e+00 0.00000000e+00 0.00000000e+00]]
我们可以看到很多第一个控制点都是零向量,我们必须分析扇区源代码来解决这个问题,我建议这样做:
class Circ(Scene):
def construct(self):
shape = Sector(
color=GOLD_B,
fill_color=GOLD_B,
fill_opacity=1,
stroke_width=4,
stroke_color=TEAL,
angle=360*DEGREES
)
shape.points = shape.points[32:-1] # <- because there are 33 zero vectors at the beginning and 1 at the end
self.play(
ShowCreation(
shape,
run_time=4,
rate_func=lambda t: linear(1-t)
)
)
self.wait()
显然,零的数量可能会根据Sector
我们使用的 mobject 而变化,因此您必须找到一种方法来过滤开头那些不必要的零向量,也许这可以在 Sector 类的定义中轻松纠正.